Ms Access Vba Overflow Error
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Runtime Error 6 Overflow
be auto redirected in 1 second. Reference Trappable Errors Core Visual Basic Language Errors Core Visual Basic Language Errors runtime error 6 overflow excel vba 6 Overflow 6 Overflow 6 Overflow 3 Return without GoSub 5 Invalid procedure call or argument 6 Overflow 7 Out of memory 9 Subscript out of range 10 This array is fixed runtime error 6 overflow vba or temporarily locked 11 Division by zero 13 Type mismatch 14 Out of string space 16 Expression too complex 17 Can't perform requested operation 18 User interrupt occurred 20 Resume without error 28 Out of stack space 35 Sub, Function, or Property not defined 47 Too many DLL application clients 48 Error in loading DLL 49 Bad DLL calling convention 51 Internal error 52
How To Fix Runtime Error 6 Overflow
Bad file name or number 53 Can't find specified file 54 Bad file mode 55 File already open 57 Device I\O error 58 File already exists 59 Bad record length 61 Disk full 62 Input past end of file 63 Bad record number 67 Too many files 68 Device unavailable 70 Permission denied 71 Disk not ready 74 Can't rename with different drive 75 Path\File access error 76 Path not found 91 Object variable or With block variable not set 92 For loop not initialized 93 Invalid pattern string 94 Invalid use of Null 96 Can't sink this object's events because it's already firing events... 97 Can't call Friend procedure on an object that isn't an instance of... 98 A property or method call cannot include a reference to a private ... 321 Invalid file format 322 Can't create necessary temporary file 400 Form already displayed; can't show modally 422 Property not found 429 ActiveX component can't create object or return reference to this... 430 Class doesn't support Automation 432 File name or class name not found during Automation operation 438 Object doesn't support this property or method 440 Automat
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Vba Overflow Integer
just like you, helping each other. Join them; it only takes a minute: Sign up MS Access Overflow Error up vote 1 down vote favorite I am getting an Overflow error in Access when this line https://msdn.microsoft.com/en-us/library/aa264525(v=vs.60).aspx runs intAT = Nz(DLookup("at_ID", "qryAT", "at_sc_ID=" & Me.sc_ID & " AND at_OT=0"), 0) If I add Debug.Print Nz(DLookup("at_ID", "qryAT", "at_sc_ID=" & Me.sc_ID & " AND at_OT=0"), 0) just before that line, it prints the id number just fine, but still errors during the assignment on the next line. I can also get it to work by adding a criterion to the query that limits all the results to those that occur before a certain http://stackoverflow.com/questions/19099354/ms-access-overflow-error day and time. It ONLY works limiting the query to before that particular time, not after an earlier time. If any of the records after that time are included, it overflows again. I have looked at the data that was entered after that time and it all seems fine, but I am not sure what exactly I should be looking for. The at_ID associated with the first record that causes it to fail is 32838 if that helps at all. vba ms-access access-vba share|improve this question edited Sep 30 '13 at 16:45 HansUp 79.3k114371 asked Sep 30 '13 at 16:36 philthyfool 74312 convert intAT to double. –Santosh Sep 30 '13 at 16:38 add a comment| 1 Answer 1 active oldest votes up vote 3 down vote accepted My guess is that intAT was declared as Integer type. But 32,838 is too large for an Integer. (Integer can hold numbers from –32,768 to 32,767) So it triggers error #6, "Overflow". Use a Long Integer instead. Dim lngAT As Long lngAT = Nz(DLookup("at_ID", "qryAT", "at_sc_ID=" & Me.sc_ID & " AND at_OT=0"), 0) share|improve this answer edited Sep 30 '13 at 17:28 answered Sep 30 '13 at 16:43 HansUp 79.3k114371 I believe, as per Access 2007, int gets implicitly dimensioned as a long. –Elias Sep 30 '13 at 17
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers http://stackoverflow.com/questions/28053343/runtime-error-6-overflow or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it https://www.youtube.com/watch?v=EMOYJK_x4Mk only takes a minute: Sign up runtime error 6 overflow up vote 2 down vote favorite I am getting a Runtime error 6 'overflow' message on the following code upon arriving at the line starting with 'minimo'. It was working error 6 fine until recently. After providing some cosmetic-type updates to its underlying form this message has arrived and I can't understand why. 'Dim rs As ADODB.Recordset Set rs = New ADODB.Recordset rs.Open "select min(autonumerazione) from tblDashboard01", CurrentProject.Connection Do While Not rs.EOF minimo = rs.Fields(0) rs.MoveNext Loop minimo = minimo - 1 st_Sql = "update tbldashboard01 set MasterLevel = autonumerazione - " & minimo & "" Application.DoCmd.RunSQL (st_Sql) access-vba ms-access-2010 share|improve this question edited Jan 20 '15 at 19:16 HansUp 79.3k114371 asked runtime error 6 Jan 20 '15 at 19:11 Marchese Il Chihuahua 4601826 How is minimo declared? If it's Integer, it can't accept a value larger than 32,767. What is the value of rs.Fields(0) when you hit that error? –HansUp Jan 20 '15 at 19:14 add a comment| 1 Answer 1 active oldest votes up vote 3 down vote accepted Try inserting the following line at the start of the program: Dim minimo as Long share|improve this answer answered Jan 20 '15 at 19:23 miroxlav 5,66121744 bravo. Thank you –Marchese Il Chihuahua Jan 20 '15 at 19:39 3 @MarcheseIlChihuahua – My practice is to insert Option Explicit as the first line of every program module (file). This forces me to declare every variable using Dim statement and this way I can avoid many errors similar to this one. –miroxlav Jan 20 '15 at 21:06 Miroxlav, just as an FYI i had declared that variable as Integer prior to taking your advice. After a bit of research it seemed to me that this problem resulted from the fact that the underlying field which was being extracted was an automatic numerical field which was exceeding a large number. I am still a bit confused as to why this is a problem . –Marchese Il Chihuahua Jan 21 '15 at 6:59 1 @MarcheseIlChihuahua - honestly, I'm not sure how automatic data types work in some scenarios. The
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