Function Is Not Defined Javascript Error
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Uncaught Referenceerror Function Is Not Defined Javascript
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Function Is Not Defined Jquery
minute: Sign up Why is my JavaScript function sometimes “not defined”? up vote 29 down vote favorite 8 I call my JavaScript function. Why do I sometimes get the error 'myFunction is not defined' when it is defined? For example. I'll occasionally get 'copyArray is not defined' even in this example: function copyArray( pa ) { var la = []; for uncaught referenceerror function is not defined onclick (var i=0; i < pa.length; i++) la.push( pa[i] ); return la; } Function.prototype.bind = function( po ) { var __method = this; var __args = []; // Sometimes errors -- in practice I inline the function as a workaround. __args = copyArray( arguments ); return function() { /* bind logic omitted for brevity */ } } As you can see, copyArray is defined right there, so this can't be about the order in which script files load. I've been getting this in situations that are harder to work around, where the calling function is located in another file that should be loaded after the called function. But this was the simplest case I could present, and appears to be the same problem. It doesn't happen 100% of the time, so I do suspect some kind of load-timing-related problem. But I have no idea what. @Hojou: That's part of the problem. The function in which I'm now getting this error is itself my addLoadEvent, which is basically a standard version of the common library function. @James: I understand that, and there is no s
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Referenceerror Function Is Not Defined Jquery
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Uncaught Referenceerror Function Is Not Defined Jquery
about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack uncaught referenceerror variable is not defined Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping http://stackoverflow.com/questions/153909/why-is-my-javascript-function-sometimes-not-defined each other. Join them; it only takes a minute: Sign up Javascript/Jquery- “$ is not defined- $function()” Error up vote 12 down vote favorite 3 I am trying to run a javascript/jquery function and firebug gets the error: $ is not defined $(function()". The javascript is placed inside a file called core.js and referenced by index.php. What http://stackoverflow.com/questions/10779148/javascript-jquery-is-not-defined-function-error causes this error? JavaScript: PHP/html javascript jquery share|improve this question edited Oct 24 '13 at 20:08 Eric Leschinski 46.7k23221190 asked May 28 '12 at 3:50 CodingWonders90 1,47632351 1 Do you have jQuery referenced? –Sampson May 28 '12 at 3:51 1 Um.. You are putting
& Guides Learn the Web Tutorials References Developer Guides Accessibility Game development ...more docs Mozilla Docs Add-ons https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Errors/Not_defined Firefox WebExtensions Developer ToolsFeedback Get Firefox help Get web development help Join the MDN community Report a content problem Report a bug Search Search Languages Deutsch (de) Français (fr) 日本語 (ja) 한국어 (ko) 中文 (简体) (zh-CN) Add a translation Edit Advanced Advanced History Print this article MDN Web technology For developers JavaScript JavaScript reference JavaScript is not error reference ReferenceError: "x" is not defined Your Search Results fscholz ReferenceError: "x" is not defined In This Article MessageError typeWhat went wrong?ExamplesVariable not declaredWrong scopeSee also Message ReferenceError: "x" is not defined Error type ReferenceError. What went wrong? There is a non-existent variable referenced somewhere. This variable needs to be declared, or you need is not defined make sure it is available in your current script or scope. Note: When loading a library (such as jQuery), make sure it is loaded before you access library variables, such as "$". Put the script tag that loads the library before your code that uses it. Examples Variable not declared foo.substring(1); // ReferenceError: foo is not defined The "foo" variable isn't defined anywhere. It needs to be some string, so that the String.prototype.substring() method will work. var foo = "bar"; foo.substring(1); // "ar" Wrong scope A variable need to be available in the current context of execution. Variables defined inside a function cannot be accessed from anywhere outside the function, because the variable is defined only in the scope of the function function numbers () { var num1 = 2, num2 = 3; return num1 + num2; } console.log(num1); // ReferenceError num1 is not defined. However, a function can access all variables and functions defined inside the scope in which it is defined. In