$ Is Not A Function Break On This Error $document.readyfunction
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies typeerror is not a function javascript of this site About Us Learn more about Stack Overflow the company typeerror $ is not a function wordpress Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges jquery(...).ready(...) is not a function Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a uncaught typeerror: document.ready is not a function minute: Sign up TypeError: jQuery(…).ready(…) is not a function up vote 16 down vote favorite OK, I know this has been asked before but none of the answers seems to apply to my case. I'm trying to get a very tiny piece of jQuery running (I'm just getting started on it). jQuery(document).ready(function(){ jQuery('.comtrig').on('click',function(){ $(this).next().animate({'display':'inline'},1000); }); })(); I get the error TypeError: jQuery(...).ready(...)
Uncaught Typeerror $(...).ready Is Not A Function Magento
is not a function in FF or Uncaught TypeError: object is not a function in Chrome. Solution 1 was to replace $ with jQuery but I obviously already did that as shown above I'm not in Wordpress either I'm using only jQuery and the above mini script, no other JS jQuery itself seems to load fine What am I missing here? javascript jquery share|improve this question asked Feb 13 '14 at 13:17 RubenGeert 1,22341434 1 What happens if you type $ or jQuery into console in browser? –Purple Hexagon Feb 13 '14 at 13:19 2 Just to be sure, are you loading jQuery before your jQuery(...).ready(...) call? –Niet the Dark Absol Feb 13 '14 at 13:19 what is the order of jquery file including? –ɹɐqʞɐ zoɹǝɟ Feb 13 '14 at 13:20 4 I think there is a typo })(); –Satpal Feb 13 '14 at 13:20 1 Replace })(); with });, This is incorrect {()) –Satpal Feb 13 '14 at 13:26 | show 3 more comments 5 Answers 5 active oldest votes up vote 23 down vote accepted tr
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting
Type Error Is Not A Function Angularjs
ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join typeerror is not a function firefox the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes $ is not a function jquery a minute: Sign up TypeError: $ is not a function when calling jQuery function up vote 93 down vote favorite 31 I have a simple jQuery script in a WordPress plugin that is using a jQuery wrapper like this: $(document).ready(function(){ // http://stackoverflow.com/questions/21755397/typeerror-jquery-ready-is-not-a-function jQuery code is in here }); I am calling this script from within the WordPress Dashboard and am loading it AFTER the jQuery framework has loaded. When I check the page in Firebug I constantly keep receiving the error message: TypeError: $ is not a function $(document).ready(function(){ Should I maybe wrap the script in this function: (function($){ // jQuery code is in here })(jQuery); I have had this error quite a few times and am not sure how to handle it. Any http://stackoverflow.com/questions/12343714/typeerror-is-not-a-function-when-calling-jquery-function help would be greatly appreciated. jquery wordpress function wrapper typeerror share|improve this question edited Apr 7 '15 at 14:34 Craig London 391410 asked Sep 9 '12 at 23:05 Jason 1,301113452 1 If you type $ in console and press enter - what do you see? –zerkms Sep 9 '12 at 23:08 When running $ in console I receive "undefined" –Jason Sep 9 '12 at 23:21 add a comment| 12 Answers 12 active oldest votes up vote 155 down vote accepted By default when you enqueue jQuery in Wordpress you must use jQuery, and $ is not used (this is for compatibility with other libraries). Your solution of wrapping it in function will work fine, or you can load jQuery some other way (but that's probably not a good idea in Wordpress). If you must use document.ready, you can actually pass $ into the function call: jQuery(function ($) { ... share|improve this answer edited Nov 27 '12 at 19:47 answered Sep 9 '12 at 23:10 Explosion Pills 120k28148226 2 or simply (function($){ // jQuery code here })(jQuery); –Jason Sep 9 '12 at 23:18 I tried the second version however it didn't work, the first version did but I just want to make sure I am not doubling up on calling jQuery. –Jason Sep 9 '12 at 23:19 @Jason you don't even need that; just exactly what I posted: jsfiddle.net/vcbYJ –Explosion Pills Sep 9 '12 at 23:24
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with http://stackoverflow.com/questions/12166883/type-error-is-not-a-function us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Type Error $ is not a function up vote 3 down vote favorite I am using a jQuery Based Memory Game on my site. It works well overall but I want a "Play Again" Link and stats at the end to show. is not I cannot get that code to work. I see this error: TypeError: $ is not a function [Break On This Error] var game = $('div.slashc-memory-game'); // get the game Here is the JS: // this script shows how you can get info about the game var game = $('div.slashc-memory-game'); // get the game var info = $('p#info').find('span'); // get the info box var playAgain = $('a#play-again').css('visibility', 'hidden'); // get the play again link // format time like hh:mm:ss var formatTime = function(s) { var is not a h = parseInt(s / 3600), m = parseInt((s - h * 3600) / 60); s = s % 60; return (h < 10 ? '0' + h : h) + ':' + (m < 10 ? '0' + m : m) + ':' + (s < 10 ? '0' + s : s); } // listen for game 'done' event game.bind('done', function(e) { // show basic stats var stats = game.slashcMemoryGame('getStats'); info.html('Success ! Number of clicks : ' + stats.numClicks + ', elapsed time : ' + formatTime(parseInt(stats.time / 1000)) + '.'); playAgain.css('visibility', 'visible'); // show link }); // play again action playAgain.click(function(e) { playAgain.css('visibility', 'hidden'); // hide link info.html('Memory Game, click to reveal images'); // reset text game.slashcMemoryGame('restart'); // restart game e.preventDefault(); }); Here is a Fiddle javascript jquery share|improve this question asked Aug 28 '12 at 20:16 L84 20.7k35116197 1 SyntaxError: missing } after function body –Dr.Molle Aug 28 '12 at 20:19 It doesn't make a lot of sense to set up a fiddle that doesn't mimic the actual problem. –Pointy Aug 28 '12 at 20:20 1 Your site works fine for me. The fiddle, however, is full of copy-and-paste errors –Eric Aug 28 '12 at 20:23 1 Your code works fine.. so does the 'Play Again' link - Chrome 21.0.1180.83 m –ᾠῗᵲᄐᶌ Aug 28 '12 at 20:37 add a comment| 4 Answers 4 active oldest votes up vote 1 down vote accepted Try replacing $() with jQuery() and see if you continue