Mysqli Bind_param Error
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Call To A Member Function Bind_param() On A Non-object
just like you, helping each other. Join them; it only takes a minute: Sign up mysqli bind_param() fatal error up vote 1 down vote favorite I Have an Error at my Code could someone help me? prepare($sql); $stmt->bind_param("i", $owner_ID); $stmt->execute(); $stmt->bind_results($name, $kalender_ID); while ($stmt->fetch()) { echo $name . " " . $kalender_ID; } ?> When I open it this error appears "Fatal error: Call to a member function bind_param() on a non-object in G:\xampp\htdocs\Karmintalender\test.php on line 8" php mysqli share|improve this question asked Jul 5 '11 at 12:18 Rafael Marques 4791519 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted One of your fields on this line doesn't exist,check them. $sql = "SELECT name, kalender_ID FROM kalender WHERE ersteller_ID = ?"; Also, you should be checking for $stmt. $db = new mysqli("localhost","root","","karmintalender"); $owner_ID = 1; $sql = "SELECT name, kalender_ID FROM kalender WHERE ersteller_ID = ?"; $stmt = $db->prepare($sql); if($stmt){ $stmt->bind_param("i", $owner_ID); $stmt->execute(); $stmt->bind_results($name, $kalender_ID); while ($stmt->fetch()) { echo $name . " " . $kalender_ID; } } share|improve this answer answered Jul 5 '11 at 12:23 Eddie 6,87221729 right the field kalender_ID doesn't exist I now edited it and there is another er
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up PHP bind_param error up vote 1 down vote favorite When I start my script this Error appears: Fatal error: Call to a member function bind_param() http://stackoverflow.com/questions/6582512/mysqli-bind-param-fatal-error on a non-object in /Applications/XAMPP/xamppfiles/htdocs/Jil/login_skript.php on line 16 Here is the script: $sql = "SELECT ID, vorname, nachname, username, email, passwort, profilBild, geschlecht, alter, wohnort, ueberSich FROM benutzer WHERE username LIKE '?' LIMIT 1;"; $stmt = $db->prepare($sql); $stmt->bind_param("s", $username); php mysqli share|improve this question asked Jul 14 '11 at 15:51 Rafael Marques 4791519 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted The problem is that 'alter' is a MySQL http://stackoverflow.com/questions/6696123/php-bind-param-error keyword. Enclose all your field names (or at least just 'alter') in backticks to fix this. Also, don't put quotes around the '?'s in a prepared statement. They will be added for you. $sql = "SELECT `ID`, `vorname`, `nachname`, `username`, `email`, `passwort`, `profilBild`, `geschlecht`, `alter`, `wohnort`, `ueberSich` FROM `benutzer` WHERE `username` LIKE ? LIMIT 1;"; $stmt = $db->prepare($sql); $stmt->bind_param("s", $username); share|improve this answer answered Jul 14 '11 at 16:00 Rocket Hazmat 131k20190257 Thank you that was correct :) –Rafael Marques Jul 14 '11 at 18:07 You're welcome. –Rocket Hazmat Jul 14 '11 at 18:10 add a comment| up vote 1 down vote This occurs because your select statement is invalid and the prepare returns NULL. You don't need the ' around the ?. There may be other errors as well that you can see by calling $db->error share|improve this answer answered Jul 14 '11 at 15:56 Rodaine 783411 there is still the same error –Rafael Marques Jul 14 '11 at 15:57 add this after the prepare statement: –Rodaine Jul 14 '11 at 15:57 if (!$stmt) echo $db->error; and see what it says. –Rodaine Jul 14 '11 at 15:58 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Em
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow http://stackoverflow.com/questions/11816481/mysqli-bind-param-fails-but-why the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up mysqli bind_param fails but why? up vote 1 down vote favorite The following error triggers a mysql call to error, this is due to query not binding the parameter to the statement. I do not understand why this is happening. This is the error returned by the else clause: ERROR -> 1064 : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? ORDER BY dateCreated DESC' at line 4` Here is the code in call to undefined question: $userId = 1; if ($stmt = $link->query(" SELECT o.id, dateCreated, firstValue FROM user_orders o LEFT JOIN order_delivery d ON o.id = d.id WHERE o.userId = ? ORDER BY dateCreated DESC ")) { $stmt->bind_param("i", $userId); $stmt->execute(); $stmt->close(); } else { $pageContent = '
ERROR -> '.$link->errno.' : '.$link->error.'
'; } Could someone possibly point our where i have gone wrong with this and why this mysql error is occuring. Thank you for taking the time to read through this! php binding mysqli share|improve this question edited Aug 5 '12 at 12:46 Mat 136k21235274 asked Aug 5 '12 at 12:38 Craig van Tonder 1,58893459 add a comment| 1 Answer 1 active oldest votes up vote 4 down vote accepted Use mysqli::prepare, not query to prepare your prepared statement. query will try to run that query which isn't valid until the parameters have been bound. share|improve this answer answered Aug 5 '12 at 12:47 Mat 136k21235274 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Not the answer you'r