Cannot Be Dereferenced Error
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn
Error Int Cannot Be Dereferenced Java
more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags error char cannot be dereferenced java Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you,
Int Cannot Be Dereferenced Compareto
helping each other. Join them; it only takes a minute: Sign up “Char cannot be dereferenced” error up vote 4 down vote favorite I'm trying to use the char method isLetter(), which is supposed to return boolean value int cannot be dereferenced length corresponding to whether the character is a letter. But when I call the method, I get an error stating that "char cannot be dereferenced." I don't know what it means to dereference a char or how to fix the error. the statement in question is: if (ch.isLetter()) { .... .... } Any help? What does it mean to dereference a char and how do I avoid doing so? java char dereference share|improve this question edited Oct 19 int cannot be dereferenced for loop '12 at 9:13 amesh 94221338 asked Apr 3 '11 at 2:05 user658168 3524713 1 Don't try to call methods on primitives. How about Character.isLetter(ch); –Hovercraft Full Of Eels Apr 3 '11 at 2:08 add a comment| 4 Answers 4 active oldest votes up vote 11 down vote The type char is a primitive -- not an object -- so it cannot be dereferenced Dereferencing is the process of accessing the value referred to by a reference. Since a char is already a value (not a reference), it can not be dereferenced. use Character class: if(Character.isLetter(c)) { share|improve this answer edited Apr 3 '11 at 2:18 answered Apr 3 '11 at 2:09 manji 36.3k36183 1 +1 - though it should also be noted that the . in Character.isLetter(c) denotes the use of a static method of Character. –Stephen C Apr 3 '11 at 3:34 add a comment| up vote 0 down vote I guess ch is a declared as char. Since char is a primitive data type and not and object, you can't call any methof from it. You should use Character.isLetter(ch). share|improve this answer answered Apr 3 '11 at 2:09 MByD 97.8k17184213 add a comment| up vote 0 down vote A char doesn't have any methods - it's a Java primitive. You're looking for the Character wrapper class. The usage would be: if(Character.isLetter(ch)) { //.
New Topic programming forums Java Java JSRs Mobile Certification Databases Caching Books Engineering Languages Frameworks Products This Site
Int Cannot Be Dereferenced Java Meaning
Careers Other all forums Forum: Beginning Java int cannot be dereferenced int cannot be dereferenced equals java error Collete Williams Greenhorn Posts: 4 posted 5 years ago I know this error has
Int Cannot Be Dereferenced Tostring
been written numerous times, but I am still confused about why I received the error. I am very new to Java, this is my first and last http://stackoverflow.com/questions/5527114/char-cannot-be-dereferenced-error programming class. This is the first time I have seen this error and lost. I know it has something to do with the int and string. I am confused all together how it works. Code is suppose to accept an integer from user, go thru the array and find the element of that array and https://coderanch.com/t/536655/java/java/int-dereferenced-error display in a textfield. It also has to handle 2 specific exceptions. Can someone please tell me what it is suppose to look like. Thank you.. int cannot be dereferenced-line 53 //import java.lang.*; public class showElement implements ActionListener{ public void actionPerformed(ActionEvent e){ randomNumber = new int [100]; for (int x = 0; x < randomNumber.length; x++) randomNumber[x] = (int)(Math.random() * 1000); String inputString; inputString=valueField.getText(); try{ valueField.setText(randomNumber[Integer.parseInt(inputString)].toString());//error section } catch (IndexOutOfBoundsException ex){ valueField.setText("Out of bounds"); } catch (NumberFormatException ex){ valueField.setText("Not a Integer."); } } } Kurt Van Etten Ranch Hand Posts: 98 posted 5 years ago 1 Hi Collete, and welcome to the Ranch! The error you're getting, in line 17 of the code excerpt you posted, is because you're trying to call the toString() method on an int (since that's what's stored in the array), and int is a primitive type. There are several ways you could convert the int to a String: for example, you could concat it wi
MUZ140721 Bothwell Nhidza MUZ140721 Bothwell Nhidza 4,286 Points Int cannot be dereferenced I am trying to convert the https://teamtreehouse.com/community/int-cannot-be-dereferenced above code to string but all methods are producing an error LandingActivity.java import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.EditText; public class LandingActivity extends Activity { public Button mThrustButton; public TextView mTypeLabel; public EditText mPassengersField; public Spaceship mSpaceship; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_landing); mThrustButton = (Button)findViewById(R.id.thrustButton); mTypeLabel = (TextView)findViewById(R.id.typeTextView); mPassengersField = cannot be (EditText)findViewById(R.id.passengersEditText); mSpaceship=new Spaceship("FIREFLY"); mTypeLabel.setText(mSpaceship.getType()); mPassengersField.setText((mSpaceship.getNumPassengers()).toString()); // Add your code here! } } Spaceship.java public class Spaceship { private String mType; private int mNumPassengers = 0; public String getType() { return mType; } public void setType(String type) { mType = type; } public int getNumPassengers() { return mNumPassengers; } public void setNumPassengers(int numPassengers) { mNumPassengers cannot be dereferenced = numPassengers; } public Spaceship() { mType = "SHUTTLE"; } public Spaceship(String type) { mType = type; } } Evan Anger Treehouse Guest Teacher Evan Anger Evan Anger Treehouse Guest Teacher >1y ago Doing a quick pass through on the code, can you call out what line of code is giving you the "Int cannot be deferenced" compile error? This will aid others in helping with a solution. 1 Answer James Simshaw 28,723 Points James Simshaw James Simshaw 28,723 Points over 1 year ago Hello, ints are a primative type and do not have a toString method. The common way on Treehouse videos to convert an int to a string is to concatinate it with an empty string String someString = 12345 + ""; Another way is to use the toString static method on the Integer class String someString = Integer.toString(12345); Posting to the forum is only allowed for members with active accounts. Please sign in or sign up t