Error Sending Message Over Socket.6
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up C Sockets - Messages are only sent once up vote 1 down vote favorite 1 I am trying to create a little https://msdn.microsoft.com/en-us/library/windows/desktop/ms740668(v=vs.85).aspx Fileserver with the files only in the shared memory. The client is supposed to send commands to the server like CREATE, DELETE, etc. However, I am not at that stage yet. I have prepared a server and a client. The server accepts a socket and created a new thread for each client connecting (requirement). When I start a client, I can successfully connect to the server and send a message which will be received. http://stackoverflow.com/questions/23653753/c-sockets-messages-are-only-sent-once However, this works only once. After my command has been sent the server will not receive any other commands. I tried to catch the messages using a line breaker but this doesn't seem to work, so any help would be appreciated. Thanks in advance. Server Source: /* * main.c - the server file. * * Created on: Apr 26, 2014 * Author: fish-guts */ #include "main.h" /* our main server buffer */ char serverbuf[4096]; static int client_sock; void launch_app(char *argv[]) { if ((strcmp(argv[1], "start")) == 0) startup(); else if ((strcmp(argv[1], "stop")) == 0) stop_server(); else { fprintf(stderr, "Invalid Command: %s. Valid Commands are ./fileserver [start|stop]\n", argv[1]); exit(EXIT_FAILURE); } } int main(int argc, char* argv[]) { if (argc > 1) launch_app(argv); else { fprintf(stderr, "No argument supplied. Valid Argument are [start|stop]\n"); exit(EXIT_SUCCESS); } return 0; } void print_start_msg(void) { fprintf(stderr, "###############################\n"); fprintf(stderr, "Welcome to Severin'ŝ FileServer\n"); fprintf(stderr, "###############################\n"); } void stop_server(void) { exit(EXIT_SUCCESS); } void startup(void) { print_start_msg(); start_server(); } void start_server(void) { int s, len, rc; int tid; long t; char buf[100000]; struct sockaddr_in addr; struct sockaddr_in client; pthread_t client_thread; sock = socket(AF_INET, SOCK_STREAM, 0); unsigned short port = PORT; // clear the struct memset((char*) &addr, 0, sizeof(addr)); fprintf(stderr, "\n\nStarting server..."); // let's set some values /* type of socket created in socket() */ addr.sin_family = AF_INET; addr.sin_addr.s_addr = INADDR_A
Sign in Pricing Blog Support Search GitHub This repository Watch 46 Star 231 Fork 119 kerryjiang/SuperWebSocket Code Issues 22 Pull requests 0 Projects 0 https://github.com/kerryjiang/SuperWebSocket/issues/6 Pulse Graphs New issue Sending a second message from client to server fails #6 Open KBeoughter opened this Issue Jan 20, 2014 · 9 comments Projects None yet Labels http://www.binarytides.com/programming-udp-sockets-in-python/ None yet Milestone No milestone Assignees No one assigned 2 participants KBeoughter commented Jan 20, 2014 Using the latest source from Github for SuperSockets, SuperWebSockets, WebSocket4Net and SuperSocket.ClientEngine error sending I can open a connection from a Client to a server (WebSockets) and send as many message from the server to the client that I want. However whenever I try to send more than one message from the client to the server connection is closed. I have track this down to a change you made in "SuperSocket/SocketBase/AppSession.cs". You added the error sending message line "var currentRequestLength = m_ReceiveFilter.LeftBufferSize" to the "FilterRequest" method (line 504 in the latest version on github). When this method is called for the second message sent from the client m_frame used in the property get method, LeftBufferSize, is null and causes a null reference exception to occur. Note, the first time it is not null. I was able to work around this by checking for null in the LeftBufferSize property get method. I don't think this is a good solution since I think what you are trying to handle large data frames being sent from a client and my "kludge" won't do that. Owner kerryjiang commented Jan 20, 2014 If so, there must be an exception logged. Could you send me the error log? KBeoughter commented Jan 20, 2014 [System.NullReferenceException] = {System.NullReferenceException: Object reference not set to an instance of an object. at SuperWebSocket.Protocol.WebSocketDataFrameReceiveFilter.get_LeftBufferSize() in v:\Code\src\Mono\SuperWebSocketServerLibrary\SuperWebSocket\SuperWebSocket\Protocol\WebSocketDataFrameReceiveFilter.cs:line 24 at SuperSocket.SocketBase.AppSession`2.FilterRequest(Byte[] readBuffer, Int32 offset, Int32 length, Boolean toBeCopied, Int32& rest, Int32& offsetDelta) in v:\Code\src\Mono\SuperWebSocketServerLibrary\SuperSocket\SocketBase\AppSession.cs:line 504 at SuperSocket.SocketBase.AppSession`2.SuperSocket.SocketBase.IAppSession.ProcessRequest(Byte[] readBuffer, Int32 offset, Int32 length, Boolean toBeCopied) in v:\Code\src\Mono\SuperWebSocketServerLibrary\SuperSocket\SocketBase\AppSession.cs:line 562 at SuperSocket.SocketEngine.AsyncSocketSession.ProcessR
General Freelancing Networking Virtualbox Windows Windows 8 Linux Hardware Linux Commands Reviews Security Burp Suite Kali Linux Metasploit Server FTP Http Monitoring Smtp Super Tips Programming udp sockets in python Python By Silver Moon On Oct 16, 2012 16 Comments UDP sockets UDP or user datagram protocol is an alternative protocol to its more common counterpart TCP. UDP like TCP is a protocol for packet transfer from 1 host to another, but has some important differences. UDP is a connectionless and non-stream oriented protocol. It means a UDP server just catches incoming packets from any and many hosts without establishing a reliable pipe kind of connection. In this article we are going to see how to use UDP sockets in python. It is recommended that you also learn about programming tcp sockets in python. Create udp sockets A udp socket is created like this s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) The SOCK_DGRAM specifies datagram (udp) sockets. Sending and Receiving Since udp sockets are non connected sockets, communication is done using the socket functions sendto and recvfrom. These 2 functions dont require the socket to be connected to some peer. They just send and receive directly to and from a given address Udp server The simplest form of a udp server can be written in a few lines import socket port = 5000 s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) s.bind(("", port)) print "waiting on port:", port while 1: data, addr = s.recvfrom(1024) print data A udp server has to open a socket and receive incoming data. There is no listen or accept. Run the above server from a terminal and then connect to it using ncat. Ncat is a telnet alternative that is more powerful and more featureful. $ ncat localhost 5000 -u -v Ncat: Version 6.00 ( http://nmap.org/ncat ) Ncat: Connected to 127.0.0.1:5000. hello ok The u flag indicates the udp protocol. Whatever message we send, should display on the server terminal. Lets write a complete echo server now. ''' Simple udp socket server ''' import socket import sys HOST = '' # Symbolic name meaning all available interfaces PORT = 8888 # Arbitrary non-privileged port # Datagram (udp) socket try : s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) print 'Socket created' except socket.error, msg : print 'Failed to create socket. Error Cod