Handle Error Ms Access Query
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Replace #error With 0 In Access
with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million http://answers.microsoft.com/en-us/msoffice/forum/msoffice_access-mso_other/how-to-handle-error-return-on-query/6ed55033-f88d-4bce-a264-33f9f70481e6 programmers, just like you, helping each other. Join them; it only takes a minute: Sign up #Func! Error on iif query in MS Access up vote 1 down vote favorite Below is my sql query: IIf(remedy_src.Position Is Null,(mid(remedy_src.User,instr(1,remedy_src.User,"(")+1,instr(1,remedy_src.User,")")-2-instr(1,remedy_src.User,"(")+1)),remedy_src.Position) AS [Adjusted User] The point is to extract string from a field. Here's an example of the http://stackoverflow.com/questions/31313926/func-error-on-iif-query-in-ms-access value: n123456 (name lastname) the IIf function returns what is in the brackets: name lastname But. Sometimes the source value looks like that: n123456 No brackets, and the IIf returns the ugly #Func! error which prevents the query to be refreshed in my excel file (external data connection to access db). I would like to handle this error somehow. Preferably to make the IIf function return raw source value if error is present. sql ms-access share|improve this question edited Jul 10 '15 at 15:16 Newd 2,01111028 asked Jul 9 '15 at 9:47 Adrian Chrostowski 55113 add a comment| 3 Answers 3 active oldest votes up vote 1 down vote You could try to catch the error: IIF(IsERROR(IIf(remedy_src.Position Is Null,(mid(remedy_src.User,instr(1,remedy_src.User,"(")+1,instr(1,remedy_src.User,")")-2-instr(1,remedy_src.User,"(")+1)),remedy_src.Position)), remedy_src.user, IIf(remedy_src.Position Is Null,(mid(remedy_src.User,instr(1,remedy_src.User,"(")+1,instr(1,remedy_src.User,")")-2-instr(1,remedy_src.User,"(")+1)),remedy_src.Position)) AS [Adjusted User] or IIF(InStr("(",remedy_src.user)=0, remedy_src.user, IIF(IsERROR(IIf(remedy_src.Position Is Null,(mid(remedy_src.User,instr(1,remedy_src.User,"(")+1,instr(1,remedy_src.User,")")-2-instr(1,remedy_src.User,"(")+1)),remedy_src.Position)) As [Adjusted User] share|improve this answer edited Jul 9 '15 at 12:46 answered Jul 9 '15 at 10:40 Gene 27229 nope. Syntax error (missing operator) in query expression –Adrian Chro
MariaDB PostgreSQL SQLite MS Office Excel Access Word Web Development HTML CSS Color Picker Languages C Language More ASCII Table Linux https://www.techonthenet.com/access/queries/divide_by_zero.php UNIX Java Clipart Techie Humor Advertisement Access Topics Combo Boxes Constants Database Date/Time Forms Functions Modules/VBA Queries Question/Answer Reports Security Shortcuts Standards Subforms Switchboard Tables Text boxes MS Access 2003: Handling Divide by Zero errors in queries This MSAccess tutorial explains how to handle divide by zero errors in queries in Access 2003 ms access (with screenshots and step-by-step instructions). See solution in other versions of Access: Access 2007 Access 2003 Question: In Microsoft Access 2003/XP/2000/97, I'm trying to write a formula in a query as follows: [Price]/[Quantity] Most of the times this formula works, but in some cases the [Quantity] field is zero so when the formula divides handle error ms zero by zero, the result comes up as #Error. Is there a way I can tell Access, if dividing by zero, the result is zero? Answer: You can use the iif function in your Access query to handle these cases. We'll demonstrate how to do this with the example below. In this example, we've used the iif function to return 0 if the [Quantity] is 0. Otherwise, it would return the value of [Price] divided by [Quantity]. This is achieved with the following formula: IIf([Quantity]=0,0,[Price]/[Quantity]) Now, your Access query should no longer return an error when a [Quantity] of 0 is encountered. Share this page: Advertisement Back to top Home | About Us | Contact Us | Testimonials | Donate While using this site, you agree to have read and accepted our Terms of Service and Privacy Policy. We use advertisements to support this website and fund the development of new content. Copyright © 2003-2016 TechOnTheNet.com. All rights reserved.