Ms Access 2010 Error 2447
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FORUMSFOR COMPUTER PROFESSIONALS Log In Come Join Us! Are you aComputer / IT professional?Join Tek-Tips Forums! Talk With Other Members Be Notified Of ResponsesTo Your Posts Keyword Search One-Click Access To YourFavorite Forums Automated SignaturesOn Your Posts Best Of All, It's Free! Join Us! *Tek-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail. Posting Guidelines Promoting, selling, recruiting, coursework and thesis posting is forbidden.Tek-Tips Posting Policies Jobs Jobs from Indeed What: Where: jobs by Link To This Forum! Add Stickiness To Your Site By Linking To This Professionally Managed Technical Forum.Just copy and http://answers.microsoft.com/en-us/msoffice/forum/msoffice_access-mso_winother/access-2010-error-2447-when-trying-to-access/b20c9cdb-2cd3-48a2-aa71-ee044a1691b3 paste the BBCode HTML Markdown MediaWiki reStructuredText code below into your site. Microsoft: Access Forms Forum at Tek-Tips HomeForumsProgrammersDBMS PackagesMicrosoft: Access Forms Forum Run Time Error '2447', form used to work. thread702-1712014 Forum Search FAQs Links MVPs Run Time Error '2447', form used to work. Run Time Error '2447', form used to work. Triacona (TechnicalUser) (OP) 4 Jun 13 10:24 Hello everybody! Thanks for an amazing forum! http://www.tek-tips.com/viewthread.cfm?qid=1712014 I was checking some of my Access Databases and have just recently encountered an error. Quote (error)Run Time Error '2447' There is an invalid use of the .(dot) or ! operator or invalid parenthesesWe have just recently upgraded to Microsoft Office 2010, including MS Access 2010. On opening the DB a few missing references were listed in VB. I removed those and checked if (what I think) the core references were still intact. Then the DB opened without missing reference errors. I then clicked a button on my MainScreen form, which opens another form Questionnaire. This then gives me the error message: Quote (error)Run Time Error '2447' There is an invalid use of the .(dot) or ! operator or invalid parentheses Then I debug and it goes to the following code in the Questionnaire form. The following code appears: CODE --> vbaPrivate Sub Form_Current() If Me.NewRecord = True Then Me.DateInterview.SetFocus End If 'FIX!!!!!!!!!!! If txtCurrentRecord = Me.txtTotalRecords Then DateInterview.SetFocus cmdNextRecord.Enabled = False cmdPrevRecord.Enabled = True Else cmdNextRecord.Enabled = True If txtCurrentRecord = 1 Then DateInterview.SetFocus cmdNextRecord.Enabled = True cmdPrevRecord.Enabled = False Else cmdPrevRecord.Enabled = True End If End If End Sub The above (just below Fix!!!) gets highlighted. What I don't unders
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About http://stackoverflow.com/questions/19054138/access-vba-checkbox-error-2447 Us Learn more about Stack Overflow the company Business Learn more about hiring http://www.utteraccess.com/forum/run-time-error-2447-t1941901.html developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Access VBA Checkbox error 2447 up ms access vote 0 down vote favorite Ok, I'm getting the error 2447 when trying to create a new record in my database. Here is the code that is have. 'This checks the record each time a record is changed to see if it needs to display the text boxes Private Sub Form_Current() If Me.SigCheck = 1 then <--This is where I'm getting the error. SigSerialtxt.Visible = True ms access 2010 SigSeriallbl.Visible = True SigAssettxt.Visible = True SigAssetlbl.Visible = True Else SigSerialtxt.Visible = False SigSeriallbl.Visible = False SigAssettxt.Visible = False SigAssetlbl.Visible = False End if End Sub I've tried to change the variable to True, as well as -1, but neither of the work. I'm lost as to what to use. access-vba share|improve this question asked Sep 27 '13 at 15:07 user1827407 61 1 Error 2447 is about "... an invalid use of the . (dot) or ! operator or invalid parentheses." So the problem is with Me.SigCheck, not what's on the right side of the = sign. What is Me.SigCheck? –HansUp Sep 27 '13 at 16:00 Me.SigCheck is a checkbox, I want the form to check each time a record is pulled up to see if value of the item is true. If it is true then display the textboxes. –user1827407 Sep 30 '13 at 18:55 Does this show you the checkbox value or does it throw an error?: MsgBox Me.SigCheck –HansUp Sep 30 '13 at 19:12 When I added the msgbox statement I get the error when hitting new record. But only when hitting new record. If I'm look
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