Ms Access Datediff #error
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Datediff Access
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just like you, helping each other. Join them; it only takes a minute: Sign up DateDiff Access Query returning #Error up vote 2 down vote favorite I am trying to get the number of days between two dates. Here is the Expression I am using in Access Query Designer. (Access 2007) Expr1: DateDiff('d',[Accept Date],[Sent Date]) The
Ms Access Datediff Hours And Minutes
query is returning #Error. The [Accept Date] and [Sent Date] format is yyyymmdd and the Data Type is TEXT. I changed it to Date/Time but Access purged the data. Here is the SQL behind the Query if that helps: SELECT RTG.[PRO NO], RTG.[Service], RTG.[Sent Date], RTG.[Accept Date], DateDiff('d',[Accept Date],[Sent Date]) AS Expr1 FROM RTG WHERE (((RTG.[PRO NO Prefix])<>"215") AND ((RTG.[Invoice Number])="8548")); This has got to be something simple, right? sql ms-access ms-access-2007 share|improve this question edited Oct 9 '14 at 14:41 HansUp 79.3k114371 asked Oct 9 '14 at 14:14 Derek 1361615 add a comment| 1 Answer 1 active oldest votes up vote 3 down vote accepted DatePart can accept dates which are actually text instead of Date/Time datatype. However, the text must be something which Access recognizes as a valid date representation. A text date in "yyyymmdd" format doesn't satisfy that requirement. For example, in the Immediate window ... ? IsDate("20141009") False However, if you insert dashes between the year, month, and day segments, A
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DatePart DateSerial DateValue Day Format (with Dates) Hour Minute Month MonthName Now Second Time TimeSerial TimeValue Weekday datedif excel 2010 WeekdayName Year Advanced/Logical Functions Information Functions Domain Aggregate Functions Data Type Conversion Functions Group By Functions File/Directory Functions MS Access: DateDiff Function This MSAccess tutorial explains how to use http://stackoverflow.com/questions/26280722/datediff-access-query-returning-error the Access DateDiff function with syntax and examples. Description The Microsoft Access DateDiff function returns the difference between two date values, based on the interval specified. Syntax The syntax for the DateDiff function in MS Access is: DateDiff ( interval, date1, date2, [firstdayofweek], [firstweekofyear]) Parameters or Arguments interval The interval of time to use to calculate the difference https://www.techonthenet.com/access/functions/date/datediff.php between date1 and date2. Below is a list of valid interval values. Interval Explanation yyyy Year q Quarter m Month y Day of year d Day w Weekday ww Week h Hour n Minute s Second date1 and date2 The two dates to calculate the difference between. firstdayofweek Optional. It is a constant that specifies the first day of the week. If this parameter is omitted, Access assumes that Sunday is the first day of the week. This parameter can be one of the following values: Constant Value Explanation vbUseSystem 0 Use the NLS API setting vbSunday 1 Sunday (default) vbMonday 2 Monday vbTuesday 3 Tuesday vbWednesday 4 Wednesday vbThursday 5 Thursday vbFriday 6 Friday vbSaturday 7 Saturday firstweekofyear Optional. It is a constant that specifies the first week of the year. If this parameter is omitted, Access assumes that the week containing Jan 1st is the first week of the year. This parameter can be one of the following values: Constant Value Explanation vbUseSystem 0 Use the NSL API settin
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To: Access 2016, Access 2013, Access 2010, Access 2007, Access 2010 Developer, Access 2007 Developer, Access 2013 Developer, Less Applies To: Access 2016 , Access 2013 , Access 2010 , Access 2007 , Access 2010 Developer , Access 2007 Developer , Access 2013 Developer , More... Which version do I have? More... Returns a Variant (Long) specifying the number of time intervals between two specified dates. See some examples Syntax DateDiff ( interval, date1, date2 [, firstdayofweek] [, firstweekofyear] ) The DateDiff function syntax has these arguments: Tip: In Access 2010, the Expression Builder has IntelliSense, so you can see what arguments your expression requires. Argument Description interval Required. String expression that is the interval of time you use to calculate the difference between date1 and date2. date1, date2 Required. Variant (Date). Two dates you want to use in the calculation. firstdayofweek Optional. A constant that specifies the first day of the week. If not specified, Sunday is assumed. firstweekofyear Optional. A constant that specifies the first week of the year. If not specified, the first week is assumed to be the week in which January 1 occurs. Settings The intervalargument has these settings: Setting Description yyyy Year q Quarter m Month y Day of year d Day w Weekday ww Week h Hour n Minute s Second Top of Page The firstdayofweek argument has these settings: Constant Value Description vbUseSystem 0 Use the NLS API setting. vbSunday 1 Sunday (default) vbMonday 2 Monday vbTuesday 3 Tuesday vbWednesday 4 Wednesday vbThursday 5 Thursday vbFriday 6 Friday vbSaturday 7 Saturday Constant Value Description vbUseSystem 0 Use the NLS API setting. vbFirstJan1 1 Start with week in which January 1 occurs (default). vbFirstFourDays 2 Start with the first week that has at least four days in the new year. vbFirstFullWeek 3 Start with first full week of the year. Remarks You can use the DateDiff function to determine how many specified time intervals exist between two dates. For example, you might use DateDiff to calculate the number of days between two dates, or the number of weeks between today and the end of the year. To calculate the number of days between date1 and date2, you can use either Day of year ("y") or Day ("d"). When interval is Weekday ("w"), DateDiff returns the number of weeks between the two dates. If date1 falls on a Monday, DateDiff counts the number of Mondays until date2. It counts date2 but not date1. If interval is Week ("ww"), however, the DateDiff function returns the number of calendar weeks between the two dates. It counts the number of S