Ms Access Error 3022
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Error 3022 Cannot add a duplicate value because of https://support.microsoft.com/en-us/kb/966136 a key constrain up vote -1 down vote favorite I am trying to insert a value into a table and i am getting an error 3022(It says that there might be a problem with a relation, a key or index). I have not created the table myself but i found out the specific column that triggers the error. I have checked that its not a key, index http://stackoverflow.com/questions/20180847/error-3022-cannot-add-a-duplicate-value-because-of-a-key-constrain and there is not a relation to that table that depends on that specific column. Is there anything i can do to avoid that error? Thanks in advance. ms-access-2010 share|improve this question asked Nov 24 '13 at 20:53 Stamatis Liatsos 548 add a comment| 1 Answer 1 active oldest votes up vote 2 down vote accepted No offense intended, but I tend to believe the application. There must be an index or a relation that you believe is innocuous but is actually the cause of the error. Therefore, I recommend the following: In Access, with all tables closed, click the "Database Tools" tab on the ribbon and then click the "Database Documenter" button in the "Analyze" section of the ribbon bar. In the dialog box that appears, place a checkmark beside the table in question and then click the "Options..." button. In the options dialog, make sure that the highest level of detail is selected: Click "OK" to close the Print Table Definition dialog, then click "OK" again to run the Documenter report. Study the report carefully. If you don't see the cause of your error then, in the "Data" section of the ribbon, click "PDF or XPS". Save the report
for Help Receive Real-Time Help Create a Freelance Project Hire for a Full Time Job Ways to Get Help Ask a Question Ask for Help Receive Real-Time Help Create a https://www.experts-exchange.com/questions/28081512/Access-Error-3022-Update-of-question-Access-is-creating-duplicate-Autonumber-PK.html Freelance Project Hire for a Full Time Job Ways to Get http://www.utteraccess.com/forum/index.php?showtopic=1078148 Help Expand Search Submit Close Search Login Join Today Products BackProducts Gigs Live Careers Vendor Services Groups Website Testing Store Headlines Experts Exchange > Questions > Access Error 3022. (Update of question) Access is creating duplicate Autonumber PK. Want to Advertise Here? Solved Access Error 3022. (Update of ms access question) Access is creating duplicate Autonumber PK. Posted on 2013-03-30 MS Access 1 Verified Solution 20 Comments 1,371 Views Last Modified: 2013-03-30 I will leave the rest of the question as is BUT I have confirmed that Access 2007 is generating a duplicate PK when it is set to: Autonumber Long Increment No Duplicates Allowed Field name is SL_PK and ms access error it is selected as PK and is indexed. Screen shot attached. Any ideas how to overcome this? My code works 99% of the time but once and awhile I get Access Error 3022: The changes you requested to the table were not successful because they would create duplicate values in the primary index, primary key, or relationship... The code is an edit mode that I created that deletes all records from the table where criteria are found. There can be unlimited records based on what is in tblMulti. There is a typical PK in each and it is set to autonumber no duplicates allowed. I can not find where I went wrong. Can you please look at this and point me in a direction to fix it? Thanks PBLack 'delete original records and this works 100% of the time strDelete = "DELETE * FROM tblStandImprovement WHERE SL_BLNUM = '" & Trim(Me.txtBlNum) & "' AND SL_SECT = '" & Format(Me!txtSect, "00") & "' AND SL_INV = '" & Me.txtInv & "';" db.Execute (strDelete) 'cycle through tblMulti
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