Cannot Be Dereferenced Java Error
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Int Cannot Be Dereferenced Java Meaning
Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, int cannot be dereferenced java helping each other. Join them; it only takes a minute: Sign up “int cannot be dereferenced” in Java up vote 9 down vote favorite 2 I'm fairly new to Java and I'm using BlueJ. I keep getting this
Int Cannot Be Dereferenced Tostring
"Int cannot be dereferenced" error when trying to compile and I'm not sure what the problem is. The error is specifically happening in my if statement at the bottom, where it says "equals" is an error and "int cannot be dereferenced." Hope to get some assistance as I have no idea what to do. Thank you in advance! public class Catalog { private Item[] list; private int size; // Construct an empty catalog with the specified int cannot be dereferenced length capacity. public Catalog(int max) { list = new Item[max]; size = 0; } // Insert a new item into the catalog. // Throw a CatalogFull exception if the catalog is full. public void insert(Item obj) throws CatalogFull { if (list.length == size) { throw new CatalogFull(); } list[size] = obj; ++size; } // Search the catalog for the item whose item number // is the parameter id. Return the matching object // if the search succeeds. Throw an ItemNotFound // exception if the search fails. public Item find(int id) throws ItemNotFound { for (int pos = 0; pos < size; ++pos){ if (id.equals(list[pos].getItemNumber())){ //Getting error on "equals" return list[pos]; } else { throw new ItemNotFound(); } } } } java int bluej share|improve this question edited Jul 19 at 0:13 Sotirios Delimanolis 154k25245361 asked Oct 1 '13 at 6:08 BBladem83 183129 2 You're trying to using a int where an Integer, Number or Object is expected...int does not have any methods –MadProgrammer Oct 1 '13 at 6:09 add a comment| 5 Answers 5 active oldest votes up vote 9 down vote accepted id is of primitive type int and not an Object. You cannot call methods on a primitive as you are doing here : id.equals Try replacing this: if (id.equals(list[pos].getItemNumber())){ //Getting error on "equals" with if (id == list[pos].getItemNumber()){ //Getting error on "equals" share|impr
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Int Cannot Be Dereferenced Equals Java
forums Forum: Beginning Java int cannot be dereferenced error Collete
Int Cannot Be Dereferenced Compareto
Williams Greenhorn Posts: 4 posted 5 years ago I know this error has been written numerous times, java int cannot be dereferenced array but I am still confused about why I received the error. I am very new to Java, this is my first and last programming class. This is the http://stackoverflow.com/questions/19109131/int-cannot-be-dereferenced-in-java first time I have seen this error and lost. I know it has something to do with the int and string. I am confused all together how it works. Code is suppose to accept an integer from user, go thru the array and find the element of that array and display in a textfield. It also has https://coderanch.com/t/536655/java/java/int-dereferenced-error to handle 2 specific exceptions. Can someone please tell me what it is suppose to look like. Thank you.. int cannot be dereferenced-line 53 //import java.lang.*; public class showElement implements ActionListener{ public void actionPerformed(ActionEvent e){ randomNumber = new int [100]; for (int x = 0; x < randomNumber.length; x++) randomNumber[x] = (int)(Math.random() * 1000); String inputString; inputString=valueField.getText(); try{ valueField.setText(randomNumber[Integer.parseInt(inputString)].toString());//error section } catch (IndexOutOfBoundsException ex){ valueField.setText("Out of bounds"); } catch (NumberFormatException ex){ valueField.setText("Not a Integer."); } } } Kurt Van Etten Ranch Hand Posts: 98 posted 5 years ago 1 Hi Collete, and welcome to the Ranch! The error you're getting, in line 17 of the code excerpt you posted, is because you're trying to call the toString() method on an int (since that's what's stored in the array), and int is a primitive type. There are several ways you could convert the int to a String: for example, you could concat it with an empty string to have it implicitly converted, or you could use the static Int
New Topic programming forums Java Java JSRs Mobile Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Java in General char cannot be dereferenced preethi Ayyappan Ranch Hand Posts: 518 posted 8 years https://coderanch.com/t/384636/java/java/char-dereferenced ago Hi,The below is a part of a code in my program to split a https://teamtreehouse.com/community/help-with-error-code-boolean-cannot-be-dereferenced sentence to a particular part(ie). "sip show peers" displays the output like this: Name/username Host Dyn Nat ACL Port Status 5102/5102 (Unspecified) D 0 Unmonitored Here i need to take the Name/username separately.for that i have tried the following code. public class HelloLive extends JApplet implements ActionListener { String command="sip show peers"; public void run() throws ManagerCommunicationException { for (String cannot be string : asteriskServer.executeCliCommand(command)) { String b; char a; for(int i=0;i
with error code: "Boolean cannot be dereferenced" So i'm new to this and during my challenge i keep getting this error message but i can't figure out how to fix it, or rather what i'm doing wrong i suppose. I thought i did it right, can anyone explain to me what i'm doing wrong? Thank you! ~Ryan Example.java // I have initialized a java.io.Console for you. It is in a variable named console. String question; boolean response; do { question = console.readLine("Do you understand do while loops? "); response = (question.equalsIgnoreCase("yes")); if (response) { console.printf("Congrats"); } } while(response); 1 Answer MOD Rob Bridges Java Web Development Treehouse Moderator 13,395 Points Rob Bridges Rob Bridges Java Web Development Treehouse Moderator 13,395 Points over 1 year ago Hey there Rian, The trouble that is getting caused is because you're trying to set up your boolean, I think that java thinks you're trying to change the value to be the string representation of true, instead of a boolean. In reality you have all the code that you need to pass this challenge minus a few adjustments (good job). The first thing to do is take out the boolean. Also, be sure to name your string as response, otherwise the challenge won't allow you to move on to the next step, so it should look something like, and when we're checking to see if we want to break out of the loop, check to see if the response is equal to no. Other than that, good job again! String response; do { response = console.readLine("Do you understand do while loops? "); } while(response.equalsIgnoreCase("no")); Thanks I hope this helps, feel free to shout at me if it doesn't. Ryan Loveland 328 Points Ryan Loveland Ryan Loveland 328 Points >1y ago Ooohhh okay, the course just prior to the quiz was talking about booleans in the end, so when the question talked about storing the answer i assumed thats what it was asking me to do, lol. i'm still a little unclear about how "do" and "while" works, but hopefully it'll be discussed more in the next courses. Thank you very much for your help, i really appreciate it :) ~Ryan Rob Bridges Java Web Development Treehouse Moderator 13,395 Points Rob Bridges Rob Bridges Java Web Development Treehouse Moderator 13,395 Points >1y ago Hey Rian, no worries, this was actually a really well done, it looks like you trying to overcomplicate it a bit. Happens to the best of us. A do while loop is more or less like this do do { //the code that you want to be repeated until a certain condition is met } while (//condition that if met continues the loop) The while part of it is always a little sketchy at first, but think of it this way, in a do while