Cannot Dereferenced Error
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Error Int Cannot Be Dereferenced Java
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Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only int cannot be dereferenced length takes a minute: Sign up Error of int cannot be dereferenced? up vote 0 down vote favorite I am getting an error with this constructor, and i have no idea how to fix? I am a beginner at java. This is from an example exercise that i was trying to learn: /** * Create an array of size n and int cannot be dereferenced for loop store a copy of the contents of the * input argument * @param intArray array of elements to copy */ public IntArray11(int[] intArray) { int i = 0; String [] Array = new String[intArray.length]; for(i=0; i here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users int cannot be dereferenced equals java Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up “Char cannot be dereferenced” error up vote 4 down vote favorite I'm trying to use the char method isLetter(), which is supposed to return boolean value corresponding http://stackoverflow.com/questions/28213083/error-of-int-cannot-be-dereferenced to whether the character is a letter. But when I call the method, I get an error stating that "char cannot be dereferenced." I don't know what it means to dereference a char or how to fix the error. the statement in question is: if (ch.isLetter()) { .... .... } Any help? What does it mean to dereference a char and how do I avoid doing so? java char dereference share|improve this question edited Oct 19 '12 http://stackoverflow.com/questions/5527114/char-cannot-be-dereferenced-error at 9:13 amesh 94221338 asked Apr 3 '11 at 2:05 user658168 3524713 1 Don't try to call methods on primitives. How about Character.isLetter(ch); –Hovercraft Full Of Eels Apr 3 '11 at 2:08 add a comment| 4 Answers 4 active oldest votes up vote 11 down vote The type char is a primitive -- not an object -- so it cannot be dereferenced Dereferencing is the process of accessing the value referred to by a reference. Since a char is already a value (not a reference), it can not be dereferenced. use Character class: if(Character.isLetter(c)) { share|improve this answer edited Apr 3 '11 at 2:18 answered Apr 3 '11 at 2:09 manji 36.3k36183 1 +1 - though it should also be noted that the . in Character.isLetter(c) denotes the use of a static method of Character. –Stephen C Apr 3 '11 at 3:34 add a comment| up vote 0 down vote I guess ch is a declared as char. Since char is a primitive data type and not and object, you can't call any methof from it. You should use Character.isLetter(ch). share|improve this answer answered Apr 3 '11 at 2:09 MByD 97.8k17184213 add a comment| up vote 0 down vote A char doesn't have any methods - it's a Java primitive. You're looking for the Character wrapper class. The usage would be: if(Character.isLetter(ch)) { //... } share|improve New Topic programming forums Java Java JSRs Mobile Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Beginning Java int cannot be dereferenced error https://coderanch.com/t/536655/java/java/int-dereferenced-error Collete Williams Greenhorn Posts: 4 posted 5 years ago I know this error has been written numerous times, but I am still confused about why I received the error. I am very new to https://teamtreehouse.com/community/gokartjava18-error-int-cannot-be-dereferenced-error Java, this is my first and last programming class. This is the first time I have seen this error and lost. I know it has something to do with the int and string. I cannot be am confused all together how it works. Code is suppose to accept an integer from user, go thru the array and find the element of that array and display in a textfield. It also has to handle 2 specific exceptions. Can someone please tell me what it is suppose to look like. Thank you.. int cannot be dereferenced-line 53 //import java.lang.*; public class showElement implements ActionListener{ public cannot be dereferenced void actionPerformed(ActionEvent e){ randomNumber = new int [100]; for (int x = 0; x < randomNumber.length; x++) randomNumber[x] = (int)(Math.random() * 1000); String inputString; inputString=valueField.getText(); try{ valueField.setText(randomNumber[Integer.parseInt(inputString)].toString());//error section } catch (IndexOutOfBoundsException ex){ valueField.setText("Out of bounds"); } catch (NumberFormatException ex){ valueField.setText("Not a Integer."); } } } Kurt Van Etten Ranch Hand Posts: 98 posted 5 years ago 1 Hi Collete, and welcome to the Ranch! The error you're getting, in line 17 of the code excerpt you posted, is because you're trying to call the toString() method on an int (since that's what's stored in the array), and int is a primitive type. There are several ways you could convert the int to a String: for example, you could concat it with an empty string to have it implicitly converted, or you could use the static Integer.toString() method to explicitly convert it . Collete Williams Greenhorn Posts: 4 posted 5 years ago I read up on on what it means to "concat it with an empty string" and "static Integer.toString() method" but I'm sorry I am still confused. Originally I had major help with that line but it looks like it did not work. Are you saying this line: valueField.setText(randomNumber[Integer.parseInt(inputString)].toStr int cannot be dereferenced Error ? I'm following the java track and I was trying to increment a battery charge. and I don't have any idea what this error means Brendon Butler 3,592 Points Brendon Butler Brendon Butler 3,592 Points 10mo ago Could you post your code? 1 Answer PRO Rebecca Rich Pro Student 7,102 Points Rebecca Rich Rebecca Rich Pro Student 7,102 Points 10 months ago Usually this will happen if you try to call a method on an int (which is a primitive type). So for example, something like this: int count = 1; String counterText = "count" + count.toString(); The .toString() method call directly on the integer would throw that error. If that does not help you find your problem or if you have additional questions / code snippets, let us know! Kele Heart 1,039 Points Kele Heart Kele Heart 1,039 Points 10mo ago Yes this was my problem thank you so much Posting to the forum is only allowed for members with active accounts. Please sign in or sign up to post. 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