Java Compile Error Cannot Be Dereferenced
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more int cannot be dereferenced tostring about Stack Overflow the company Business Learn more about hiring developers or posting ads int cannot be dereferenced meaning with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow int cannot be dereferenced compareto is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Error of int cannot be dereferenced? up vote 0 down vote favorite int cannot be dereferenced length I am getting an error with this constructor, and i have no idea how to fix? I am a beginner at java. This is from an example exercise that i was trying to learn: /** * Create an array of size n and store a copy of the contents of the * input argument * @param intArray array of elements to copy */ public IntArray11(int[] intArray) { int i =
Int Cannot Be Dereferenced Equals Java
0; String [] Array = new String[intArray.length]; for(i=0; i
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more
Boolean Cannot Be Dereferenced Java
about Stack Overflow the company Business Learn more about hiring developers or posting ads int cannot be dereferenced error java with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow char cannot be dereferenced java is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up New to Java and have the error “int cannot be dereferenced” up http://stackoverflow.com/questions/28213083/error-of-int-cannot-be-dereferenced vote 5 down vote favorite I'm new to java and I've been working on this exercise for a while, but keep receiving the error: int cannot be dereferenced. I saw couple of similar questions but still cannot figure out my own case. Here is the complete codes: package inclass; class OneInt { int n; OneInt(int n) { this.n = n; } @Override public boolean equals(Object that) { if (that http://stackoverflow.com/questions/15857377/new-to-java-and-have-the-error-int-cannot-be-dereferenced instanceof OneInt) { OneInt thatInt = (OneInt) that; return n.equals(thatInt.n); // error happens here } else { return false; } } public static void main(String[] args) { Object c = new OneInt(9); Object c2 = new OneInt(9); System.out.println(c.equals(c2)); System.out.println(c.equals("doesn't work")); } } Thank you very much for helping me with this little trouble. java share|improve this question edited Apr 7 '13 at 0:08 paulsm4 57.5k67192 asked Apr 7 '13 at 0:04 Tian 3313 add a comment| 2 Answers 2 active oldest votes up vote 7 down vote accepted equals is a method of a class. int is a primitive, not a class. Simply use == instead: return n == thatInt.n; share|improve this answer answered Apr 7 '13 at 0:06 Dukeling 36.4k94080 add a comment| Did you find this question interesting? Try our newsletter Sign up for our newsletter and get our top new questions delivered to your inbox (see an example). Subscribed! Success! Please click the link in the confirmation email to activate your subscription. up vote 4 down vote To compare ints, just use the == operator: if (n == thatInt.n) Note that int is not a class, so you can never use the . operator with an int variable. share|improve this answer answered Apr
Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Beginning Java int cannot be dereferenced error Collete Williams Greenhorn Posts: 4 posted 5 years ago I know this error has been https://coderanch.com/t/536655/java/java/int-dereferenced-error written numerous times, but I am still confused about why I received the error. I am very new to Java, this is my first and last programming class. This is the first time I have seen this https://teamtreehouse.com/community/int-cannot-be-dereferenced error and lost. I know it has something to do with the int and string. I am confused all together how it works. Code is suppose to accept an integer from user, go thru the array and cannot be find the element of that array and display in a textfield. It also has to handle 2 specific exceptions. Can someone please tell me what it is suppose to look like. Thank you.. int cannot be dereferenced-line 53 //import java.lang.*; public class showElement implements ActionListener{ public void actionPerformed(ActionEvent e){ randomNumber = new int [100]; for (int x = 0; x < randomNumber.length; x++) randomNumber[x] = (int)(Math.random() * 1000); String inputString; inputString=valueField.getText(); try{ valueField.setText(randomNumber[Integer.parseInt(inputString)].toString());//error section cannot be dereferenced } catch (IndexOutOfBoundsException ex){ valueField.setText("Out of bounds"); } catch (NumberFormatException ex){ valueField.setText("Not a Integer."); } } } Kurt Van Etten Ranch Hand Posts: 98 posted 5 years ago 1 Hi Collete, and welcome to the Ranch! The error you're getting, in line 17 of the code excerpt you posted, is because you're trying to call the toString() method on an int (since that's what's stored in the array), and int is a primitive type. There are several ways you could convert the int to a String: for example, you could concat it with an empty string to have it implicitly converted, or you could use the static Integer.toString() method to explicitly convert it . Collete Williams Greenhorn Posts: 4 posted 5 years ago I read up on on what it means to "concat it with an empty string" and "static Integer.toString() method" but I'm sorry I am still confused. Originally I had major help with that line but it looks like it did not work. Are you saying this line: valueField.setText(randomNumber[Integer.parseInt(inputString)].toString()); needs to changed to one of the options? Been trying for 2 weeks to get this working and I am burned out majorly and have gone brain dead. Is it possible for you to show me if not maybe a example. Campbell Ritchie Sheriff Posts: 50567 8
MUZ140721 Bothwell Nhidza MUZ140721 Bothwell Nhidza 4,286 Points Int cannot be dereferenced I am trying to convert the above code to string but all methods are producing an error LandingActivity.java import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.EditText; public class LandingActivity extends Activity { public Button mThrustButton; public TextView mTypeLabel; public EditText mPassengersField; public Spaceship mSpaceship; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_landing); mThrustButton = (Button)findViewById(R.id.thrustButton); mTypeLabel = (TextView)findViewById(R.id.typeTextView); mPassengersField = (EditText)findViewById(R.id.passengersEditText); mSpaceship=new Spaceship("FIREFLY"); mTypeLabel.setText(mSpaceship.getType()); mPassengersField.setText((mSpaceship.getNumPassengers()).toString()); // Add your code here! } } Spaceship.java public class Spaceship { private String mType; private int mNumPassengers = 0; public String getType() { return mType; } public void setType(String type) { mType = type; } public int getNumPassengers() { return mNumPassengers; } public void setNumPassengers(int numPassengers) { mNumPassengers = numPassengers; } public Spaceship() { mType = "SHUTTLE"; } public Spaceship(String type) { mType = type; } } Evan Anger Treehouse Guest Teacher Evan Anger Evan Anger Treehouse Guest Teacher >1y ago Doing a quick pass through on the code, can you call out what line of code is giving you the "Int cannot be deferenced" compile error? This will aid others in helping with a solution. 1 Answer James Simshaw 28,723 Points James Simshaw James Simshaw 28,723 Points over 1 year ago Hello, ints are a primative type and do not have a toString method. The common way on Treehouse videos to convert an int to a string is to concatinate it with an empty string String someString = 12345 + ""; Another way is to use the toString static method on the Integer class String someString = Integer.toString(12345); Posting to the forum is only allowed for members with active accounts. Please sign in or sign up to post. Our mission is to bring affordable, technology education to people everywhere, in order to help