Java Compiler Error Double Cannot Be Dereferenced
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Double Cannot Be Dereferenced Compareto
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Long Cannot Be Dereferenced Java
cannot be dereferenced? up vote 5 down vote favorite 2 String mins = minsField.getText(); int Mins; try { Mins = Integer.parseInt(mins); } catch (NumberFormatException e) { Mins = 0; } double hours = Mins / 60; hours.setText(hoursminsfield); The problem is that Double java long cannot be dereferenced tostring cannot be dereferenced. How can I fix this problem? Any help will be appriciated java double share|improve this question edited Apr 23 '12 at 2:06 paxdiablo 491k1189731422 asked Apr 23 '12 at 1:58 Daniel Donaldson 28113 What language is this? Javascript? –Mark Reed Apr 23 '12 at 2:04 Yeh man its java –Daniel Donaldson Apr 23 '12 at 2:06 12 java != javascript –David Gelhar Apr 23 '12 at 2:07 2 @Daniel, I fail to see how the compareto double java accepted answer relates to your question at all. You should have asked another question when you fixed the original problem. –paxdiablo Apr 23 '12 at 2:34 If you want to use hours as double, you have to leave int-arithmetic, which is used, if you mix an int with an literal int like 60: double hours = Mins / 60; Use a literal double like 60.0 instead. –user unknown Apr 23 '12 at 3:24 | show 1 more comment 3 Answers 3 active oldest votes up vote 11 down vote accepted EDIT 4/23/12 double cannot be dereferenced is the error some Java compilers give when you try to call a method on a primitive. It seems to me double has no such method would be more helpful, but what do I know. From your code, it seems you think you can copy a text representation of hours into hoursminfield by doing hours.setText(hoursminfield); This has a few errors: 1) hours is a double which is a primitive type, there are NO methods you can call on it. This is what gives you the error you asked about. 2) you don't say what type hoursminfield is, maybe you haven't even declared it yet. 3) it is unusual to set the value of a variable by having it be the argument to a method. It happens sometimes, but not usually. The lines of code that do what you seem to want are: String hoursrminfield; // you better declare any variable you are using /
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a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Java “double cannot be dereferenced” error - calling method on double data type http://stackoverflow.com/questions/10273949/double-cannot-be-dereferenced up vote 0 down vote favorite I'm trying to use the following method for conversion between temperature scales in Java. Problem is when I call the method I get a "double cannot be dereferenced" error. I understand that the reason is that methods cannot be called on primitive data types, and I think the solution is to use a wrapper but I'm not sure what that code would look like http://stackoverflow.com/questions/35377330/java-double-cannot-be-dereferenced-error-calling-method-on-double-data-type (my initial attempts at using Double wrapper all produced errors). public double celsius(double f) { return (f - 32.0)/1.8; } public double fahrenheit(double c) { return c * 1.8 + 32.0; } public void doConversion() { double tempC = 0.0; double tempF = tempC.fahrenheit; // double cannot be dereferenced error } java methods double wrapper share|improve this question edited Feb 17 at 8:45 asked Feb 13 at 7:32 Lauren Stephen 218 add a comment| 4 Answers 4 active oldest votes up vote 1 down vote accepted You already have the methods defined in you class. While doing conversion, you just have to call those methods like below: public void doConversion() { double tempC = 0.0; double tempF = fahrenheit(tempC); } Hope this helps! share|improve this answer answered Feb 13 at 7:37 Ravi Ranjan 523318 add a comment| up vote 1 down vote Do something like this: public class temperature{ public double T; //in C public temperature(double T){ this.T = T; } public double getC(){ return T; } public double getF(){ return T * 1.8 + 32.0; } } share|improve this answer answered Feb 13 at 7:37 S.Klumpers 33111 add a comment| up vote 1 down vote Instead of double tempF = tempC.fahrenheit; use double tempF = fahrenheit(tempC); share|
Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Java in General Java Double cannot be https://coderanch.com/t/519820/java/java/Java-Double-dereferenced dereferenced Megan Hart Greenhorn Posts: 6 posted 5 years ago Hi http://www.dreamincode.net/forums/topic/101943-double-cannot-be-dereferenced/ All, I am very new to Java and I am getting a 'Double cannot be dereferenced' error when I try to compile this code. public void actionPerformed(ActionEvent e) { Object source = e.getSource(); if (source == exitButton) System.exit(0); else if (source == calculateButton) { double sideAValue = cannot be Double.parseDouble(sideAField.getText()); double sideBValue = Double.parseDouble(sideBField.getText()); double sideCValue = Math.hypot(sideAValue, sideBValue); sideCValue.setText(Double.toString(sideCValue)); The above section of code is part of a larger program that calculates the hypotenuse of a right triangle when the user enters the two smaller sides. The error comes from this line of code: sideCValue.setText(Double.toString(sideCValue)); Could someone please help me to know how to fix this? cannot be dereferenced Christophe VerrĂ© Sheriff Posts: 14691 16 I like... posted 5 years ago Shouldn't that be sideCField.setText(Double.toString(sideCValue)); [My Blog] All roads lead to JavaRanch Christophe VerrĂ© Sheriff Posts: 14691 16 I like... posted 5 years ago And welcome to the ranch Next time you want to post some code, don't forget to UseCodeTags. This will be make it easier to read. [My Blog] All roads lead to JavaRanch Megan Hart Greenhorn Posts: 6 posted 5 years ago Yes it should be! Thanks for alerting me to that error. I will be sure to use code tags next time around! Thanks for the welcome! Post Reply Bookmark Topic Watch Topic New Topic Similar Threads creating a new JPanel from another JPanel "choice" button Double compiler error - Help! Help w/ Data Input Error Double compiler error - Help! Not being able to compile All times are in JavaRanch time: GMT-6 in summer, GMT-7 in winter Contact Us | advertise | mobile view | Powered by JForum | Copyright © 1998-2016 Paul Wheaton
Page 1 of 1 New Topic/Question Reply 12 Replies - 20893 Views - Last Post: 28 April 2009 - 04:04 AM Rate Topic: #1 seaneyb D.I.C Head Reputation: 1 Posts: 111 Joined: 09-February 09 double cannot be dereferenced Posted 27 April 2009 - 11:19 AM C:\Users\Seaneyb\Desktop\Exam Revision\Programming\Java\Projects\exam b>build src\exam.java:18: double cannot be dereferenced if (Number.startsWith("+")) ^ 1 error import java.lang.*; import java.util.*; import java.io.*; import java.net.*; public class exam extends Object { public static void main(String[] argStrings) throws Exception { ArrayList