Javac Error Cannot Be Dereferenced
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Int Cannot Be Dereferenced Java
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Int Cannot Be Dereferenced Tostring
community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up “int cannot be dereferenced” in Java up vote 9 down vote favorite 2 I'm fairly int cannot be dereferenced length new to Java and I'm using BlueJ. I keep getting this "Int cannot be dereferenced" error when trying to compile and I'm not sure what the problem is. The error is specifically happening in my if statement at the bottom, where it says "equals" is an error and "int cannot be dereferenced." Hope to get some assistance as I have no idea what to do. Thank you in advance! public class int cannot be dereferenced compareto Catalog { private Item[] list; private int size; // Construct an empty catalog with the specified capacity. public Catalog(int max) { list = new Item[max]; size = 0; } // Insert a new item into the catalog. // Throw a CatalogFull exception if the catalog is full. public void insert(Item obj) throws CatalogFull { if (list.length == size) { throw new CatalogFull(); } list[size] = obj; ++size; } // Search the catalog for the item whose item number // is the parameter id. Return the matching object // if the search succeeds. Throw an ItemNotFound // exception if the search fails. public Item find(int id) throws ItemNotFound { for (int pos = 0; pos < size; ++pos){ if (id.equals(list[pos].getItemNumber())){ //Getting error on "equals" return list[pos]; } else { throw new ItemNotFound(); } } } } java int bluej share|improve this question edited Jul 19 at 0:13 Sotirios Delimanolis 155k25248363 asked Oct 1 '13 at 6:08 BBladem83 183129 2 You're trying to using a int where an Integer, Number or Object is expected...int does not have any methods –MadProgrammer Oct 1 '13 at 6:09 add a comment| 5 Answers 5 active oldest votes up vote 9 down vote accepted id is of primitive type int and not an Object. You c
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Int Cannot Be Dereferenced Java Meaning
Williams Greenhorn Posts: 4 posted 5 years ago I know this error int cannot be dereferenced equals java has been written numerous times, but I am still confused about why I received the error. I am
Int Cannot Be Converted To String
very new to Java, this is my first and last programming class. This is the first time I have seen this error and lost. I know it has something http://stackoverflow.com/questions/19109131/int-cannot-be-dereferenced-in-java to do with the int and string. I am confused all together how it works. Code is suppose to accept an integer from user, go thru the array and find the element of that array and display in a textfield. It also has to handle 2 specific exceptions. Can someone please tell me what it is suppose to look like. http://coderanch.com/t/536655/java/java/int-dereferenced-error Thank you.. int cannot be dereferenced-line 53 //import java.lang.*; public class showElement implements ActionListener{ public void actionPerformed(ActionEvent e){ randomNumber = new int [100]; for (int x = 0; x < randomNumber.length; x++) randomNumber[x] = (int)(Math.random() * 1000); String inputString; inputString=valueField.getText(); try{ valueField.setText(randomNumber[Integer.parseInt(inputString)].toString());//error section } catch (IndexOutOfBoundsException ex){ valueField.setText("Out of bounds"); } catch (NumberFormatException ex){ valueField.setText("Not a Integer."); } } } Kurt Van Etten Ranch Hand Posts: 98 posted 5 years ago 1 Hi Collete, and welcome to the Ranch! The error you're getting, in line 17 of the code excerpt you posted, is because you're trying to call the toString() method on an int (since that's what's stored in the array), and int is a primitive type. There are several ways you could convert the int to a String: for example, you could concat it with an empty string to have it implicitly converted, or you could use the static Integer.toString() method to explicitly convert it . Collete Williams Greenhorn Posts: 4 posted 5 years ago I read up on on what it means to "conca
Join INTELLIGENT WORK FORUMSFOR COMPUTER PROFESSIONALS Log In Come Join Us! Are you aComputer http://www.tek-tips.com/viewthread.cfm?qid=1661919 / IT professional?Join Tek-Tips Forums! Talk With Other Members Be Notified Of ResponsesTo Your Posts Keyword Search One-Click Access To YourFavorite Forums Automated SignaturesOn https://answers.yahoo.com/question/index?qid=20120130072646AAdgmiM Your Posts Best Of All, It's Free! Join Us! *Tek-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive cannot be e-mail. Posting Guidelines Promoting, selling, recruiting, coursework and thesis posting is forbidden.Tek-Tips Posting Policies Jobs Jobs from Indeed What: Where: jobs by Link To This Forum! Add Stickiness To Your Site By Linking To This Professionally Managed Technical Forum.Just copy and paste the BBCode HTML Markdown MediaWiki reStructuredText cannot be dereferenced code below into your site. Java Forum at Tek-Tips HomeForumsProgrammersLanguagesJava Forum java errors- int cannot be dereferenced thread269-1661919 Forum Search FAQs Links MVPs java errors- int cannot be dereferenced java errors- int cannot be dereferenced dmcclus (TechnicalUser) (OP) 26 Sep 11 20:22 I have been tasked with changing a java file that I had to get from a decompiler. I am not so familiar and get errors compiling as follows:C:\Program Files\IBM\SQLLIB\java\jdk\bin>javac C:\jarsSrc\dbms\Main.javaC:\jarsSrc\dbms\Main.java:258: int cannot be dereferencedfor(i = Integer.valueOf(0); i.intValue() < lines.length;)^C:\jarsSrc\dbms\Main.java:260: int cannot be dereferencedif(lines[i.intValue()].equals((new StringBuilder()).append("NAME: ").append(apiname).toString()))^C:\jarsSrc\dbms\Main.java:262: int cannot be dereferencedj = Integer.valueOf(i.intValue() + 1);^C:\jarsSrc\dbms\Main.java:262: operator + cannot be applied to
Help Suggestions Send Feedback Answers Home All Categories Arts & Humanities Beauty & Style Business & Finance Cars & Transportation Computers & Internet Consumer Electronics Dining Out Education & Reference Entertainment & Music Environment Family & Relationships Food & Drink Games & Recreation Health Home & Garden Local Businesses News & Events Pets Politics & Government Pregnancy & Parenting Science & Mathematics Social Science Society & Culture Sports Travel Yahoo Products International Argentina Australia Brazil Canada France Germany India Indonesia Italy Malaysia Mexico New Zealand Philippines Quebec Singapore Taiwan Hong Kong Spain Thailand UK & Ireland Vietnam Espanol About About Answers Community Guidelines Leaderboard Knowledge Partners Points & Levels Blog Safety Tips Computers & Internet Programming & Design Next Java Help compareTo() method? public class test { public static void main (String [] args) { int x=5; int y=1; System.out.println(x.compareTo(y)); } } //simple program,wont compile. this is what i get: ----jGRASP exec: javac -g test.java test.java:7: error: int cannot be dereferenced System.out.println(x.compareTo(y)); ... show more public class test { public static void main (String [] args) { int x=5; int y=1; System.out.println(x.compareTo(y)); } } //simple program,wont compile. this is what i get: ----jGRASP exec: javac -g test.java test.java:7: error: int cannot be dereferenced System.out.println(x.compareTo(y)); ^ 1 error ----jGRASP wedge2: exit code for process is 1. ----jGRASP: operation complete. Follow 4 answers 4 Report Abuse Are you sure you want to delete this answer? Yes No Sorry, something has gone wrong. Trending Now Corey Seager Carrie Ann Inaba Asma al-Assad Jana Kramer LeBron James Car Insurance Yoko Ono Dallas Cowboys Psoriatic Arthritis Symptoms COPD Treatments Answers Relevance Rating Newest Oldest Best Answer: I don't think you quite understand how the method compareTo() works. Firstly the method is part of the String class. Therefore x needs to be a String. y should be a String also. The signature of the compareTo() method is as follows. int compareTo(String anotherString) The int is the return type. The method is part of the String class so should be called as System.out.println( x.compare(y)); There are no methods attached to any of the basic data types, int, long, byte, short, float, double, boolean or char. Have fun. Source(s): http://docs.oracle.com/javase/7/docs/api... AnalProgrammer · 5 years ago 1 Thumbs up 2 Thumbs down Comment Add a comment Submit · just now Report Abuse compareTo() is a method from the Integer class. Right now you have two in