Php Catchable Fatal Error
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Join them; it only takes a minute: Sign up How can I catch a “catchable fatal error” on PHP type hinting? up vote 74 down vote favorite 27 I am trying to implement Type Hinting of PHP5 on one of my class, class ClassA { public function method_a (ClassB $b) {} } class ClassB {} class ClassWrong{} Correct usage: catchable fatal error: object of class mysqli_result could not be converted to string $a = new ClassA; $a->method_a(new ClassB); producing error: $a = new ClassA; $a->method_a(new ClassWrong); Catchable fatal error: Argument 1 passed to ClassA::method_a() must be an instance of ClassB, instance of ClassWrong given... May I know if it is possible to catch that error(since it says "catchable")? and if yes, how? Thank you. php fatal-error type-hinting share|improve this question asked Mar 18 '10 at 8:59 hoball 1,06121315 2 For future reference: Exceptions in the engine (for PHP 7) - Beginning with PHP 7 it is possible catch fatal errors. This is also for the here discussed “Catchable fatal error” (E_RECOVERABLE_ERROR) as these be catched beginning with PHP 7.. –hakre Apr 27 '15 at 6:11 add a comment| 1 Answer 1 active oldest votes up vote 84 down vote accepted Update: This is not a catchable fatal error anymore in php 7. Instead an "exception" is thrown. An "exception" (in scare quotes) that is not derived from Exception but Error; it's still a Throwable and can be handled with a normal try-catch block. see h
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site About Us Learn more about Stack Overflow the company Business Learn more php catch fatal error about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss php catch error Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up How to ignore http://stackoverflow.com/questions/2468487/how-can-i-catch-a-catchable-fatal-error-on-php-type-hinting a PHP catchable fatal error from QueryPath? up vote 0 down vote favorite 1 I'm scraping some data from a website using QueryPath. However, every so often I receive the error message below and the script terminates. PHP Catchable fatal error: Argument 1 passed to DOMXPath::__construct() must be an instance of DOMDocument, null given, called in ....inc/QueryPath/QueryPath/CSS/DOMTraverser.php on line 417 and defined in ....inc/QueryPath/QueryPath/CSS/DOMTraverser.php http://stackoverflow.com/questions/17863787/how-to-ignore-a-php-catchable-fatal-error-from-querypath on line 467 The error doesn't give me any clues as to which line of my code the error is coming from, but assuming it was coming from $outHtml = htmlqp($outHtml); I tried prefixing the htmlqp command with @htmlqp. This didn't work, so I then tried wrapping htmlqp in a catch{} statement which didn't seem to help either. All I want to do is ignore the error and continue rather than having the script bomb out. Help! php html web-scraping fatal-error querypath share|improve this question asked Jul 25 '13 at 16:34 James Napier 342311 possible duplicate stackoverflow.com/questions/2468487/… –bitWorking Jul 25 '13 at 16:37 You don't wrap htmlqp with the catch, you wrap it with the try and then handle it in the catch block. –mc10 Jul 25 '13 at 16:49 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote accepted It's a catchable fatal error .. so catch it. If you catch it you can get a full stacktrace. Ex: try { thisfunctionthrowsanexception(); } catch (Exception $e) { var_dump(get_class($e)); echo $e->getTraceAsString(); } @ hides errors. You don't ever want to have to
Apparel forum Discussions forum Forum record_voice_over Laracasts Podcast forum Laravel Podcast Forum General PHP Catchable fatal https://laracasts.com/discuss/channels/general-discussion/php-catchable-fatal-error error PHP Catchable fatal error mvanemmerik card_membership — 1 year ago I'm receiving this error when I'm trying to move my Laravel project http://artur.ejsmont.org/blog/content/php-typehints-causing-errors-when-null-gets-passed-in to another server. Any ideas? -- [RuntimeException] Error Output: PHP Catchable fatal error: Argument 1 passed to Illuminate\ Foundation\Application::detectEnvironment() must be an instance fatal error of Closure , array given, called in /Users/mvanemmerik/song-list/bootstrap/environmen t.php on line 18 and defined in /Users/mvanemmerik/song-list/vendor/larave l/framework/src/Illuminate/Foundation/Application.php on line 290 PHP Stack trace: PHP 1. {main}() /Users/mvanemmerik/song-list/artisan:0 PHP 2. require_once() /Users/mvanemmerik/song-list/artisan:30 PHP 3. require() /Users/mvanemmerik/song-list/bootstrap/start.php:27 PHP 4. Illuminate\Foundation\Application->detectEnvironment() /Users/mva nemmerik/song-list/bootstrap/environment.php:18 Thanks. Best Answer — Thread Owner's Choice catchable fatal error school aliqsyed — 1 year ago As of this update there is no environment.php anymore https://github.com/laravel/laravel/commit/430134864642346498631ad562765d69599d6b39 You will see that the environment.php file has been taken out completely. You need to make sure that your project is current with laravel/laravel on github and after that run a composer update. Environment configuration is now done by defining APP_ENV in your .env file. This is an example of .env file APP_ENV=local DB_HOST=localhost DB_NAME=mydbname DB_USERNAME=homestead DB_PASSWORD=secret As of this update there is no environment.php anymore https://github.com/laravel/laravel/commit/430134864642346498631ad562765d69599d6b39 You will see that the environment.php file has been taken out completely. You need to make sure that your project is current with laravel/laravel on github and after that run a composer update. Environment configuration is now done by defining APP_ENV in your .env file. This is an example of .env file ~~~ APP_ENV=local DB_HOST=localhost DB_NAME=myd
Places to Visit Map Top Places to Visit File Book Reviews About Me HomePHP type hints cause catchable fatal error when argument is null PHP type hints cause catchable fatal error when argument is null May 2011 It is funny how often you can get caught by surprise that PHP is not Java. I have been using type hints in PHP for a long time but somehow i did not came across that for a long time. If you have a method that type hints the parameter you wont be able to pass null in as in PHP null is not just unknown value but it is also a type. class MyClass{ public function myMethod(SomeClass $arg){ if ($arg == null) { throw new InvalidArgumentException("arg can not be null"); } } } So i saw a method like this and i thought "ok ... no worries let me just add a test to cover the if". Unfortunately i realized quickly that it is PHP not Java and you can not pass a null into this method. You will get error as below: Catchable fatal error: Argument 1 passed to MyClass::myMethod() must be an instance of SomeClass, null given You can get around it by removing the type hint or by adding default value equal to null like: class MyClass{ public function myMethod(SomeClass $arg = null){ if ($arg == null) { throw new InvalidArgumentException("arg can not be null"); } } } Art PHP Errors Tips Comments Well if you declare them Well if you declare them before the optional param they will work fine, not sure if that is what you meant. The one below works just fine but im not sure if that is what you meant: function( SomeType somevar, OtherType optionalvar=null) cheers Art 2013-02-16 20:27 admin Hi, This is a nice trick, Hi, This is a nice trick, except that you can not pass more arguments without declaring them as optional as well. Do you have any workaround for that? sandvige 2013-02-14 06:02 sandvige Post new comment Your name (required) E-mail (required) Homepage What code is in the ima