Python Urlopen Error Error 10061
here for a quick overview of the site Help Center Detailed answers to any questions you might have errno 10061 connection refused Meta Discuss the workings and policies of this site About Us selenium winerror 10061 Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads winerror 10061 python with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, python set proxy just like you, helping each other. Join them; it only takes a minute: Sign up Using an HTTP PROXY - Python [duplicate] up vote 24 down vote favorite 30 This question already has an answer here: Proxy with urllib2 7 answers I familiar with the fact that I should set the HTTP_RPOXY environment variable to the
Python Urllib Proxy
proxy address. Generally urllib works fine, the problem is dealing with urllib2. >>> urllib2.urlopen("http://www.google.com").read() returns urllib2.URLError: or urllib2.URLError: Extra info: urllib.urlopen(....) works fine! It is just urllib2 that is playing tricks... I tried @Fenikso answer but I'm getting this error now: URLError: Any ideas? python http proxy urllib2 share|improve this question edited Apr 11 '11 at 11:35 asked Apr 11 '11 at 10:53 RadiantHex 7,7532297206 marked as duplicate by Ciro Santilli 烏坎事件2016六四事件 法轮功, Bhargav Raopython Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed. Dec 29 '15 at 18:35 This question has been asked before and already has an answer. If those answ
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Python Requests Proxy
hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask python proxy Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. python urllib2 Join them; it only takes a minute: Sign up up vote 0 down vote favorite I am using geopy to normalize some addresses http://stackoverflow.com/questions/5620263/using-an-http-proxy-python but when I try to run this code I am getting an error. urlopen error [Errno 10061] No connection could be made because the target machine actively refused it> from geopy.geocoders import Nominatim geolocator = Nominatim() rawAddress = '151 MCKINLEY AVE CAMP MEEKER CA 95419' location = geolocator.geocode(rawAddress, timeout=15) print location.address There are bunch of addresses which I need to normalize but I am not able to resolve this error. Could anyone help me? My firewall and antivirus are http://stackoverflow.com/questions/31817559/urlopen-error-errno-10061-no-connection-could-be-made-because-the-target-mach both off. I have already gone through bunch of questions in stack overflow but none is helpful. python sockets openstreetmap geopy nominatim share|improve this question asked Aug 4 '15 at 19:22 python 1,3011522 2 Whichever machine you are trying to connect to said no emphatically. Find out which host you are trying to connect to. –AlG Aug 4 '15 at 19:34 The program was running smoothly since morning and then error started coming. –python Aug 4 '15 at 19:50 2 That doesn't change the validity of @AlG's advice: whatever machine you are trying to connect to is no longer listening. –Robᵩ Aug 4 '15 at 20:01 2 Al and Rob both are right. You probably got rate-limited or banned if you were trying to scrape a "bunch of addresses", per the Nominatim usage policy. –myersjustinc Aug 4 '15 at 20:23 I just tried to run the same script from a different computer but still the same error. I pretty sure they might have restricted me for a day or banned me but running the same script in a different PC also didn't work. Any comments? –python Aug 4 '15 at 20:51 | show 4 more comments active oldest votes Know someone who can answer? Share a link to this question via email, Google+, Twitter, or Facebook. Your Answer draft saved draft discarded Sign up
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the http://stackoverflow.com/questions/26976071/getting-urllib2-urlerror-urlopen-error-errno-10061-error workings and policies of this site About Us Learn more about Stack http://stackoverflow.com/questions/15820739/python-urlerror-urlopen-error-errno-10060 Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join error 10061 them; it only takes a minute: Sign up Getting urllib2.URLError: here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python: URLError: Traceback (most recent call last): File "", line 1, in > > r = urllib2.urlopen(o) File "C:\Python27\lib\urllib2.py", line 126, in urlopen > return _opener.open(url, data, timeout) File "C:\Python27\lib\urllib2.py", line 400, in open > response = self._open(req, data) File "C:\Python27\lib\urllib2.py", line 418, in _open > '_open', req) File "C:\Python27\lib\urllib2.py", line 378, in _call_chain > result = func(*args) File "C:\Python27\lib\urllib2.py", line 1207, in http_open > return self.do_open(httplib.HTTPConnection, req) File "C:\Python27\lib\urllib2.py", line 1177, in do_open > raise URLError(err) URLError: respond after a period of time, or established connection failed > because connected host has failed to respond> I tried bypassing the g variable and trying to urlopen("http://www.google.com/") with no success either (it generates the same error after the same length of time). python python-2.7 urllib2 urllib share|improve this question edited Apr 10 '13 at 21:36 ronak 86911025 asked Apr 4 '13 at 20:08 Question3CPO 6171927 1 Works fine here. Is your internet working? –Bibhas Apr 4 '13 at 21:06 1 It works on my Win7+Python2.7. The most possible issue