Invalid Argument Error In Ms Access
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Error: 3001 Invalid Argument
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more http://stackoverflow.com/questions/31521280/ms-access-2010-resolving-invalid-argument-error about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users http://stackoverflow.com/questions/22008829/run-time-error-3001-invalid-argument-when-creating-a-table-in-access-vba Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up MS Access 2010 Resolving Invalid Argument Error up vote 0 down vote favorite I'm using a very simple query to update a field in SharePoint. The field invalid argument is a choice field and the table I'm updating indicates the exact value of one of the choices. Both SharePoint and my internal table indicate the field (Folders) is a text format. I've ran this query many times but suddenly started to receive an error: Invalid Argument I've searched online and tried everything to no avail. The database is well under the limit. The SQL: UPDATE tbltest INNER JOIN [Title Clearing] ON (tbltest.[Number] = [Title Clearing].[Number]) AND invalid argument error (tbltest.Client = [Title Clearing].Client) SET [Title Clearing].Folders = [tbltest]![Folders]; sql ms-access ms-access-2010 share|improve this question edited Jul 21 '15 at 19:27 asked Jul 20 '15 at 16:08 user3738222 13 How are you running the query? With VBA? Also, MS Access tables are different from SharePoint lists. Please specify objects used and the whole code and finally please edit by breaking code line to avoid horizontal scrolling in post. –Parfait Jul 21 '15 at 0:31 I'm manaully running the query, not in vba... Right click/Open. That is the entire code, [Title Clearing] is referring to the linked SharePoint table. I'm just trying to change the multiple choice field with a group of numbers in the tbltest table. –user3738222 Jul 21 '15 at 19:31 Perhaps you mean [tbltest].[Folders] instead of [tbltest]![Folders] in the line reading SET [Title Clearing].Folders = [tbltest]![Folders]; –xQbert Jul 21 '15 at 19:31 add a comment| active oldest votes Know someone who can answer? Share a link to this question via email, Google+, Twitter, or Facebook. Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Browse other quest
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Run-time error '3001': Invalid Argument when creating a table in Access VBA up vote 1 down vote favorite 1 When creating a table in Access VBA using the following code: Set tbl = dbs.CreateTableDef("" & strTableName & "") I get the following error: Run-time error '3001': Invalid Argument. What causes this? vba ms-access access-vba ms-access-2010 share|improve this question asked Feb 25 '14 at 8:45 BFWebAdmin 2,12763167 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote accepted The name of the table you're trying to create (in the above example expressed as strTableName) is not valid - it's probably either null or too long. The names of Access 2010 tables can be no longer than 64 characters. If strTableName is not null and has fewer than 64 characters, the above code will work perfectly. share|improve this answer edited Feb 26 '14 at 14:57 answered Feb 25 '14 at 8:45 BFWebAdmin 2,12763167 1 Or strTableName could be Null –4dmonster Feb 25 '14 at 9:52 @4dmonster - Yes, good point - in short, anything that creates an invalid table name would generate this error. –BFWebAdmin Feb 25 '14 at 10:08 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post