Python Error 22 Invalid Argument
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies oserror: [errno 22] invalid argument pickle of this site About Us Learn more about Stack Overflow the company Business python can't open file errno 22 invalid argument Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges errno 22 invalid argument socket Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: oserror 22 Sign up OSError [Errno 22] invalid argument when use open() in Python up vote 0 down vote favorite def choose_option(self): if self.option_picker.currentRow() == 0: description = open(":/description_files/program_description.txt","r") self.information_shower.setText(description.read()) elif self.option_picker.currentRow() == 1: requirements = open(":/description_files/requirements_for_client_data.txt", "r") self.information_shower.setText(requirements.read()) elif self.option_picker.currentRow() == 2: menus = open(":/description_files/menus.txt", "r") self.information_shower.setText(menus.read()) I am using resource files and something is going wrong when i am using it as argument
Oserror Errno 22 Invalid Argument Read
in open function, but when i am using it for loading of pictures and icons everything is fine. python share|improve this question edited Aug 30 '14 at 15:45 CoryKramer 52.2k93983 asked Aug 30 '14 at 15:45 eugene 1111 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote That is not a valid file path. You must either use a full path open(r"C:/description_files/program_description.txt","r") Or a relative path open("program_description.txt","r") share|improve this answer answered Aug 30 '14 at 15:47 CoryKramer 52.2k93983 add a comment| up vote 0 down vote you should add one more "/" in the last "/" of path for example: open('C:\Python34\book.csv') to open('C:\Python34\book.csv') import csv with open('C:\Python34\\book.csv', newline='') as csvfile: spamreader = csv.reader(csvfile, delimiter='', quotechar='|') for row in spamreader: print(row) share|improve this answer edited Jan 5 at 18:45 Tomasz Jakub Rup 5,06471436 answered Jan 5 at 15:58 Hiep Tran 512 1 Welcome to Stack Overflow! Whilst this may theoretically answer the question, it would be preferable to include the essential parts of the answer here, and provide the link for reference. –manetsus Jan 5 at 16:14 add a com
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Oserror: [errno 22] Invalid Argument Datetime
any questions you might have Meta Discuss the workings and python 3 oserror errno 22 invalid argument policies of this site About Us Learn more about Stack Overflow the company Business Learn more errno 22 invalid argument c about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community http://stackoverflow.com/questions/25584124/oserror-errno-22-invalid-argument-when-use-open-in-python Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up python 3.2: IOError: [Errno 22] Invalid argument: '/home/pi/data/temp/file1\n.txt' up vote 2 down vote favorite I am a newbie to python programming. I have a counter.txt file from which http://stackoverflow.com/questions/27031726/python-3-2-ioerror-errno-22-invalid-argument-home-pi-data-temp-file1-n-tx i am reading the counter value . Using this counter value, i have to create new files into some other folder like '/home/pi/data/temp/file%s.txt'%line. for eg: file1.txt, file2.txt and so on.. I have written some code for this and for some reason i am encountering the error below: IOError: [Errno 22] Invalid argument: '/home/pi/data/temp/file1\n.txt' My python code is as follows: while True: counter_file = open("counter.txt", 'r+') line = counter_file.readline() print(line) counter_file.close() file_read = open(r'/home/pi/data/temp/file%s.txt'%line, 'w') #data_line = line_read.decode("utf-8") #file_read.write("%s"%data_line) file_read.close() counter_file = open("counter.txt", 'w') line = int(line) + 1 counter_file.write("%s"%line) counter_file.truncate() counter_file.close() while i execute this, i get this traceback: File "compute1.py", line 24, in
User List Committer List Help Tracker Documentation Tracker Development Report Tracker Problem Issue24658 classification Title: open().write() fails on 2 GB+ data (OS X) Type: behavior Stage: patch review Components: Extension Modules, IO Versions: https://bugs.python.org/issue24658 Python 3.6, Python 3.5 process Status: open Resolution: Dependencies: Superseder: Assigned To: ned.deily https://github.com/dbr/tvnamer/issues/93 Nosy List: Ian Carroll, Mali Akmanalp, haypo, lebigot, matrixise, ned.deily, ronaldoussoren Priority: normal Keywords: needs review, patch Created on 2015-07-18 02:59 by lebigot, last changed 2016-10-21 21:38 by matrixise. Files File name Uploaded Description Edit issue24658.txt ronaldoussoren, 2015-07-20 12:50 review issue24658-3.6.diff matrixise, 2016-08-05 13:57 review issue24658-3.5.diff matrixise, 2016-08-05 17:28 review issue24658-2-3.6.diff invalid argument matrixise, 2016-10-21 14:25 review issue24658-3-3.6.diff matrixise, 2016-10-21 21:38 review Messages (18) msg246878 - (view) Author: Eric O. LEBIGOT (lebigot) Date: 2015-07-18 02:59 On OS X, the Homebrew and MacPorts versions of Python 3.4.3 raise an exception when writing a 4 GB bytearray: >>> open('/dev/null', 'wb').write(bytearray(2**31-1)) 2147483647 >>> open('/dev/null', 'wb').write(bytearray(2**31)) Traceback (most recent call last): File "
Sign in Pricing Blog Support Search GitHub This repository Watch 48 Star 535 Fork 72 dbr/tvnamer Code Issues 38 Pull requests 7 Projects 0 Pulse Graphs New issue Getting OSError(22, 'Invalid argument') instead of deleting files once copied (i.e. move) #93 Open felciano opened this Issue Feb 15, 2014 · 9 comments Projects None yet Labels None yet Milestone No milestone Assignees No one assigned 3 participants felciano commented Feb 15, 2014 I am trying to configure TVNamer to remove files after they have been successfully renamed and copied to a Synology NAS. The copy appears to work fine, but at the end of the copy I see OSError(22, 'Invalid argument') printed to the screen and the file isn't removed. My settings include: "move_files_enable": true, "overwrite_destination_on_rename": true, "overwrite_destination_on_move": true, "always_move": true, I've confirmed that the user account has read-write access to the file. Is there some way of getting additional info on the specific operation that resulted in the above OS error? Owner dbr commented Feb 16, 2014 Hm, strange.. In tvnamer/main.py you could change: try: cnamer.rename( new_fullpath = newFullPath, always_move = Config['always_move'], always_copy = Config['always_copy'], leave_symlink = Config['leave_symlink'], force = Config['overwrite_destination']) except OSError, e: log().warn(e) to: except OSError, e: import traceback; traceback.print_exc() log().warn(e) ..and rerun, and you'll get a full traceback felciano commented Feb 16, 2014 Well, that might be part of the issue: I don't see any use of cnamer.rename in my tvnamer/main.py. I just did a fresh install of version 2.3, and it looks like most of those calls are using cnamer.newPath instead. Some of the other parameters appear to be different as well (e.g. force = Config['overwrite_destination_on_move']) instead of force = Config['overwrite_destination'])) Am I using the wrong build? felciano commented Feb 17, 2014 I took a chance and added the traceback dump to the code that calls newPath. The error occurs when tvnamer tries to copy over the bits, last access time, etc via shutil.c