Python Socket Error 10022
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Socket Error Errno 10022 An Invalid Argument Was Supplied
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Python Winerror 10022
programmers, just like you, helping each other. Join them; it only takes a minute: Sign up socket.error errno=10022 when using socket.send(packet, (ip, port)) up vote 0 down vote favorite I learned to send packet using socket
Python Socket.accept Errno 22
by Python, but there is an error (socket.error errno=10022) when running the code below on the Windows machine, and everything works fine on the Linux. How can I fix it? try: s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_TCP) except socket.error , msg: print 'Socket could not be created. Error Code : ' + str(msg[0]) + ' Message ' + msg[1] sys.exit() s.setsockopt(socket.IPPROTO_IP, socket.IP_HDRINCL, 1) source_ip = self.source dest_ip = self.destination packet = ''; ip_header = socket error invalid argument self.construct_ip_header() tcp_header = self.construct_tcp_header() packet = ip_header + tcp_header s.sendto(packet, (dest_ip , 0 )) python sockets share|improve this question asked Sep 15 '15 at 15:30 lixiaoyu 230416 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote Error 10022 from Winsock means "Invalid argument" possibly because you're trying to mix SOCK_RAW with IPPROTO_TCP which are incompatible. The third argument is probably being ignored on linux, but windows is complaining about it. Something is also very wrong with your code sample - you've tried to open a raw socket, but are manually writing tcp and ip headers, but not handling the TCP state machine yourself? This seems highly overcomplicated unless you have some very specialist requirements. If you're just trying to open a TCP socket between this code and a server I'd suggest to go back the examples at https://docs.python.org/2/library/socket.html#example . The "Echo Client Program" looks like what you're trying to do. share|improve this answer answered Sep 15 '15 at 15:54 polhemic 864 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and python setsockopt policies of this site About Us Learn more about Stack Overflow the oserror: [winerror 10022] an invalid argument was supplied company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users python udp socket Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes http://stackoverflow.com/questions/32590031/socket-error-errno-10022-when-using-socket-sendpacket-ip-port a minute: Sign up Python Socket: WinError 10022 up vote 1 down vote favorite Some years ago, I programmed a chat with Python 3 und everything worked fine on Windows and Mac, till now. This function is executed in another script: import socket import pickle def get(sock): data, addr = sock.recvfrom(1024) data = pickle.loads(data) #to convert data back to a dictionary http://stackoverflow.com/questions/29421483/python-socket-winerror-10022 return data, addr On Mac this still works fine. But Windows throws out an Error: File "C:\Users\...\network.py", line 15, in get data, addr = sock.recvfrom(1024) OSError: [WinError 10022] An invalid argument was supplied What's the problem? EDIT: sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) python sockets python-3.x pickle recvfrom share|improve this question edited Sep 13 '15 at 4:43 Nayuki 12k52657 asked Apr 2 '15 at 20:02 Hustensaft 258 How is sock defined? –MattDMo Apr 2 '15 at 20:03 sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) –Hustensaft Apr 2 '15 at 20:04 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote I think you have to bind to the socket before calling sock.recvfrom(1024). sock.bind((YOUR_IP, PORT)) share|improve this answer answered Apr 3 '15 at 8:57 klopstedt 112 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms
here for a quick overview of the site Help Center Detailed answers to any http://stackoverflow.com/questions/29580485/python-tcp-sniffer-under-windows questions you might have Meta Discuss the workings and policies of https://msdn.microsoft.com/en-us/library/windows/desktop/ms740668(v=vs.85).aspx this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is invalid argument a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python TCP Sniffer under Windows up vote 0 down vote favorite So I am attempting to retro fit an amazing network packet sniffer already established but for linux. The basic jist an invalid argument is the code below works for socket.IPPROTO_UDP but not socket.IPPROTO_TCP. import socket #create an INET, STREAMing socket HOST = socket.gethostbyname(socket.gethostname()) # create a raw socket and bind it to the public interface s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_TCP) s.bind((HOST, 0)) # Include IP headers s.setsockopt(socket.IPPROTO_IP, socket.IP_HDRINCL, 1) # receive all packages s.ioctl(socket.SIO_RCVALL, socket.RCVALL_ON) # receive a packet packet = s.recvfrom(65565) print packet The error I get when running the above is : "line 12, in s.bind((HOST, 0)) File "", line 1, in bind socket.error: [Errno 10022] An invalid argument was supplied. If I fuss around with the above and strip it to bare min: import socket s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_TCP) # receive a packet packet = s.recvfrom(65565) print packet I get similar error but a tad diff line 7, in packet = s.recvfrom(65565) socket.error: [Errno 10022] An invalid argument was supplied The sniffer I am trying to retro fit, using same formatting etc is here: http://www.b
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