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like you, helping each other. Join them; it only takes a minute: Sign up How to get the jQuery $.ajax error response text? up vote 120 down vote favorite 23 I am sending an error response to my
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jQuery. However, I can not get the response text (in the example below this would be Gone to the beach) The only thing jQuery says is 'error'. See this example for details: php header('HTTP/1.1 500 Internal Server Error'); print "Gone to the beach" ?> jQuery $.ajax({ type: "post", data: {id: 0}, cache: false, url: "doIt.php", dataType: "text", error: function (request, error) { console.log(arguments); alert(" Can't do because: " + error); }, success: function () stack overflow error windows xp { alert(" Done ! "); } }); Now my result ist: log: [XMLHttpRequest readyState=4 status=500, "error", undefined] alert: Can't do because: error Any ideas? php javascript jquery ajax error-handling share|improve this question edited Feb 9 '15 at 15:54 robsch 3,23122450 asked Oct 28 '09 at 12:40 jantimon 17k1978139 The problem appears to be in your php code. Don't you need 2 linebreaks between headers and the body text? Does the header function handle this? –rfunduk Oct 28 '09 at 12:42 thenduks: PHP knows what it is doing. The issue is that because the HTTP status coming back is 500, $.ajax() calls the error function passed to it. –Chris Charabaruk Oct 28 '09 at 13:49 add a comment| 10 Answers 10 active oldest votes up vote 163 down vote accepted Try: error: function(xhr, status, error) { var err = eval("(" + xhr.responseText + ")"); alert(err.Message); } Look also at this encosia article for proper error handling. share|improve this answer answered Oct 28 '09 at 12:46 Alex Bagnolini 12.1k23137 69 I prefer to use JSON.parse(xhr.responseText) –Phil-R Jul 8 '13 at 20:22 32 eval is EVIL... stackoverflow.com/questions/646597/… –German Latorre Aug 8 '13 at 6:55 4 The article says it's okay to use eval in this case: "Note: I would normally recommend against using eval() to evaluate a JSON
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Business Learn more about hiring developers or posting ads with us Stack Overflow Questions stack overflow javascript error Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million stack overflow line error programmers, just like you, helping each other. Join them; it only takes a minute: Sign up jQuery Ajax error handling, show custom exception messages up vote 522 down vote favorite 189 Is there some way I can http://stackoverflow.com/questions/1637019/how-to-get-the-jquery-ajax-error-response-text show custom exception messages as an alert in my jQuery AJAX error message? For example, if I want to throw an exception on the server side via Struts by throw new ApplicationException("User name already exists");, I want to catch this message ('user name already exists') in the jQuery AJAX error message. jQuery("#save").click(function () { if (jQuery('#form').jVal()) { jQuery.ajax({ type: "POST", url: "saveuser.do", dataType: "html", data: "userId=" + encodeURIComponent(trim(document.forms[0].userId.value)), success: function (response) { jQuery("#usergrid").trigger("reloadGrid"); clear(); http://stackoverflow.com/questions/377644/jquery-ajax-error-handling-show-custom-exception-messages alert("Details saved successfully!!!"); }, error: function (xhr, ajaxOptions, thrownError) { alert(xhr.status); alert(thrownError); } }); } }); On the second alert, where I alert the thrown error, I am getting undefined and the status code is 500. I am not sure where I am going wrong. What can I do to fix this problem? jquery ajax struts custom-exceptions share|improve this question edited Sep 9 '15 at 5:43 Kasun Randika 2,14911635 asked Dec 18 '08 at 12:06 add a comment| 16 Answers 16 active oldest votes up vote 258 down vote Make sure you're setting Response.StatusCode to something other than 200. Write your exception's message using Response.Write, then use... xhr.responseText ..in your javascript. share|improve this answer answered Jan 16 '09 at 14:25 Sprintstar 4,74132544 6 This is still the correct way of doing this after 2 years and a half... :) I went a little further and actually return my own error JSON object that can handle single or multiple errors, quite good for server-side form validation. –AlexCode Jul 19 '11 at 19:28 1 Can you provide the code? –Wilson Jun 19 '14 at 11:46 @Wilson It was as shown in the other high-rated answers here. –Sprintstar Jun 19 '14 at 13:21 1 Am now in 2014. JSON dominated era. So i use xhr.responseJSON. :D &ndas
here for a quick overview of the site Help Center Detailed answers to any questions you http://stackoverflow.com/questions/8918248/ajax-success-and-error-function-failure might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of stack overflow 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Ajax Success and Error function failure up vote 7 down vote favorite 3 I am having trouble getting my jQuery ajax to work properly. It directs to the PHP page to update the database, but never returns stack overflow error back to the script for the success or error options. My code is below: $(document).ready(function(){ $("form#updatejob").submit(function() { function textreplace(x) {return text.replace(/[-[\]{}()*+?.,\\^$|#\s]/g, "\\$&");} // we want to store the values from the form input box, then send via ajax below var job = $("#job").attr("value"); var description = $("#description").val(); description.replace(/[-[\]{}()*+?.,\\^$|#\s]/g, "\\$&"); var startDate = $("#startDate").attr("value"); var releaseDate = $("#releaseDate").attr("value"); var status = $("#status").attr("value"); $.ajax({ beforeSend:textreplace(description), type: "POST", url: "updatedjob.php", data: "jobID="+ job +"& description="+ description +"& startDate="+ startDate +"& releaseDate="+ releaseDate +"& status="+ status, success: function(){ $("form#updatejob").hide(function(){$("div.success").fadeIn();}); }, error: function(XMLHttpRequest, textStatus, errorThrown) { alert("Status: " + textStatus); alert("Error: " + errorThrown); } }); return false; }); }); And the PHP: