Error 1690 Mysql
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Out Of Range Value For Column Mysql
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Bigint Unsigned Mysql
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Error 1690 (22003) Bigint Unsigned Value Is Out Of Range In
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn mysql out of range value for column integer more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags mysql out of range value for column decimal Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, mysql out of range value for column datetime helping each other. Join them; it only takes a minute: Sign up MySQL error #1690 (BIGINT UNSIGNED value is out of range) for UNIX_TIMESTAMP() up vote 0 down vote favorite i get error #1690 - BIGINT UNSIGNED value https://dev.mysql.com/doc/refman/5.5/en/out-of-range-and-overflow.html is out of range for this query: SELECT * FROM `user` WHERE ROUND( ( UNIX_TIMESTAMP() - `expire` ) / 86400 ) = 7 i read about this error in Stackoverflow and see some notes about cast but i can't apply them to this query. mysql share|improve this question edited Dec 6 '15 at 9:42 asked Dec 6 '15 at 9:31 علیرضا 5101414 What do you want to achieve? Checking if date in table is http://stackoverflow.com/questions/34115917/mysql-error-1690-bigint-unsigned-value-is-out-of-range-for-unix-timestamp one week before current date ? –lad2025 Dec 6 '15 at 9:34 i want to find records that expire 7 days later. –علیرضا Dec 6 '15 at 9:42 schema please thx –Drew Dec 6 '15 at 9:53 @Drew yes, here you are: sqlfiddle.com/#!9/78830/1 –علیرضا Dec 6 '15 at 10:04 add a comment| 2 Answers 2 active oldest votes up vote 1 down vote accepted Your second value in table will give negative result, so you get an error. To make negative results possible in your case, use before query SET sql_mode = 'NO_UNSIGNED_SUBTRACTION'; share|improve this answer answered Dec 6 '15 at 10:35 miholeus 31726 add a comment| up vote 1 down vote Schema CREATE TABLE IF NOT EXISTS `user` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `expire` int(10) unsigned NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=3 ; -- -- Dumping data for table `test` -- truncate table user; INSERT INTO `user` (`id`, `expire`) VALUES (1, 1234567890), (2, 1923456780), (3, 1449397282), (4,1449397282+3600); -- note this is based on this moment I am writing this about a day ahead Query select id,expire,seconds from ( select id,expire,TIME_TO_SEC(TIMEDIFF(from_unixtime(expire), now())) as seconds from user ) xDerived where seconds>0 and seconds<604800; -- # of seconds in a week +----+------------+---------+ | id | expire | seconds | +----+------------+---------+ | 4 | 1449400882 |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn http://stackoverflow.com/questions/11698613/bigint-unsigned-value-is-out-of-range-my-sql more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack http://nikolaynaychov.blogspot.com/2012/08/how-to-fix-mysql-error-bigint-unsigned.html Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up BIGINT UNSIGNED VALUE IS out of range My SQL up vote out of 7 down vote favorite 1 I'm getting the following error #1690 - BIGINT UNSIGNED value is out of range in '(legends.spawns.quantity - tmp_field)' Here is my query SELECT drops.common, drops.uncommon, drops.rare, drops.legendary, spawns . * , ( quantity - COUNT( game_moblist.spawn_id ) ) AS quantity_to_spawn , mobs . * FROM spawns LEFT JOIN mobs USING ( mob_id ) LEFT JOIN game_moblist USING ( spawn_id ) LEFT JOIN drops out of range ON ( SELECT MAX( level ) FROM drops WHERE drops.type = mobs.drop_list AND drops.level <= spawns.level ) GROUP BY spawn_id HAVING quantity_to_spawn >=0 AND next_spawn <=0 I've been staring at it a while the query is long I'm sorry. spawns table - count game_moblist.spawn_id is 0 for all possible rows but 1 (I deleted a row to test the query) The data otherwise is quite long and irrelevant to my question I think Any idea how to get around this error? mysql share|improve this question edited Jun 3 '14 at 6:02 Bind 175 asked Jul 28 '12 at 5:42 Shawn 1641416 add a comment| 5 Answers 5 active oldest votes up vote 17 down vote Please read "Out-of-Range and Overflow Handling". It says: As of MySQL 5.5.5, overflow during numeric expression evaluation results in an error. For example, the largest signed BIGINT value is 9223372036854775807, so the following expression produces an error. mysql> SELECT 9223372036854775807 + 1; ERROR 1690 (22003): BIGINT value is out of range in '(9223372036854775807 + 1)' To enable the operation to succeed in this case, convert the value to unsigned; mysql> SELECT CAST(9223372036854775807 AS UNSIGNED) + 1; +-------------------------------------------+ | CAST(9223372036854775807 AS UNSIGNED) + 1 | +-------------------------------------------+ | 9223372036854775808 | +-------------------------------
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