Out Of Bound Error
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here for a quick overview of the site Help Center Detailed answers to index out of bounds java any questions you might have Meta Discuss the workings and array index out of bounds c++ policies of this site About Us Learn more about Stack Overflow the company Business Learn more array index out of bounds meaning about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community array index out of bounds exception java try catch Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up How to fix array index out of bounds error? up vote 0 down vote favorite The error that I am getting Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 610
Array Index Out Of Bounds Exception 0
at Fib.sorted(Fib.java:67) at Fib.main(Fib.java:17) My code public class Fib { public static void main(String args[]) { System.out.println(Arrays.toString( fiblist) ); System.out.println(Fib.add()); System.out.println(Fib.square()); System.out.println(Fib.reversal()); System.out.println(Fib.sorted()); } public static int fiblist[] = {1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765}; public static int fiblen = fiblist.length; public Fib() { // Do nothing } public static ArrayList
range 0..9 To correct it, either change the declaration of the array, or change the formula http://www.ultrafractal.com/help/writing/reference/errors/arrayindexoutofbounds.html so the index values stay within the boundaries of the array. Notes Run-time errors are reported only when the DEBUG symbol is defined. See Debugging. When you declare an array to use it with the #x or #y predefined symbols, you need to make it one larger than the #width or #height predefined symbols to enable anti-aliasing to work. See Also Arrays Errors
Support Answers MathWorks Search MathWorks.com MathWorks Answers Support MATLAB Answers™ MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link Exchange ThingSpeak Anniversary https://www.mathworks.com/matlabcentral/answers/125375-how-to-avoid-index-out-of-bounds-error Home Ask Answer Browse More Contributors Recent Activity Flagged Content Flagged https://www.mathworks.com/matlabcentral/answers/120373-having-problem-with-error-index-out-of-bounds-numel-y-1 as Spam Help MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity Flagged Content Flagged as Spam Help Trial software ravi (view profile) 1 question 0 answers 0 accepted answers Reputation: 0 Vote0 how out of to avoid index out of bounds error Asked by ravi ravi (view profile) 1 question 0 answers 0 accepted answers Reputation: 0 on 11 Apr 2014 Latest activity Answered by Ken Atwell Ken Atwell (view profile) 2 questions 334 answers 113 accepted answers Reputation: 777 on 12 Apr 2014 643 views (last 30 days) 643 views (last 30 days) hi,I out of bound am trying excute fallowing programme,but it is showing Attempted to access proj(2); index out of bounds because numel(proj)=1 error.I was not able to solve this problem.anybody know answer suggest me.thanks in advance. I = imread('ch_text.tiff'); [row ,col]=size(I); h_proj=zeros; for i = 1:row sum=0; for j=1:col if I(i,j)==0 %black pixel found sum=sum+1; end end h_proj(i)=sum; end figure,plot(h_proj,1:row),title('horizontal projection'); nonzero_row_indx=zeros; i = 1; k = 1; while (i >= 1) && (i <= row) if h_proj(i) ~= 0 nonzero_row_indx(k) = i; k = k + 1; i = i + 1; while h_proj(i) ~= 0 i = i + 1; end nonzero_row_indx(k) = i - 1; k = k + 1; end i = i + 1; end 1 Comment Show all comments Walter Roberson Walter Roberson (view profile) 27 questions 27,803 answers 9,720 accepted answers Reputation: 50,303 on 12 Apr 2014 Direct link to this comment: https://www.mathworks.com/matlabcentral/answers/125375#comment_207662 Your code does not have a variable named "proj" Tags index out of bounds Products No products are associated with this question. Related Content 3 Answers Nitin (view profile) 7 qu
Support Answers MathWorks Search MathWorks.com MathWorks Answers Support MATLAB Answers™ MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity Flagged Content Flagged as Spam Help MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity Flagged Content Flagged as Spam Help Trial software Joey (view profile) 2 questions 0 answers 0 accepted answers Reputation: 0 Vote0 having problem with error "index out of bounds" numel (Y)=1" Asked by Joey Joey (view profile) 2 questions 0 answers 0 accepted answers Reputation: 0 on 6 Mar 2014 Latest activity Commented on by Image Analyst Image Analyst (view profile) 0 questions 20,758 answers 6,545 accepted answers Reputation: 34,874 on 7 Mar 2014 Accepted Answer by Image Analyst Image Analyst (view profile) 0 questions 20,758 answers 6,545 accepted answers Reputation: 34,874 53 views (last 30 days) 53 views (last 30 days) Hello all! I am trying to write a code that takes the noise out of bitmap images, and re-writes them as a cleaned image afterward. I'm not done with the code entirely yet, but my function file keeps spitting out the errorAttempted to access Y(8,1); index out of bounds because numel(Y)=1. Error in fixp (line 13) A = [(Y((i-1), j)),(Y((i-1),(j+1))),(Y(i,(j+1))),(Y((i+1),j)),(Y((i+1),(j+1)))]; Here is what my main file looks like: clc; clear; format compact; % Image importing A = imread('J20_pic1_noisy.bmp'); [m,n,p] = size(A); for k = [1:p]; for j = [1:n]; for i = [1:m]; Y = A(i,j,k); if Y == 0 | Y == 255; [B] = fixp(Y,i,j,m,n); end end end end and here is what the function file looks like: function[B] = fixp(Y,i,j,m,n); B = []; if i == 1 & j == 1 % top left corner A = [(Y(i, j+1)),(Y(i+1,j)),(Y(i+1,j+1))]; B(i, j)= mean(median(A)); elseif i == 1 & j > 1 & j < n %top side A = [(Y(i, j-1)),(Y(i,j+1)),(Y(i+1,j-1)),(Y(i+1,j)),(Y(i+1,j+1))]; B(i, j)= mean(median(A)); elseif i == 1 & j == n % top right corner A = [(Y(i, j-1)),(Y(i+1,j-1)),(Y(i+1,j))]; B(i, j)= mean(median(A)); elseif i > 1 & i < m & j == 1 % left side A = [(Y(i-1, j)),(Y(i-1,j+1)),(Y(i,j+1)),(Y(i+1,j)),(Y(i+1,j+1))]; B(i, j)= mean(median(A)); elseif i > 1 & i < m & j == n % right side A = [(Y(i-1, j-1)),(Y(i-1,j)),(Y(i,j-1)),(Y(i+1,j-1)),(Y(i+1,j))]; B(i, j)= mean(median(A)); elseif i == m & j == 1 %bottom left corner A = [(Y(i-1, j)),(Y(i-1,j+1)),(Y(i,j+1))]; B(i, j)= mean(median(A)); elseif i == m & j > 1 & j < n