Out Of Bound Exception Error
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How To Solve Array Index Out Of Bounds Exception In Java
programmers, just like you, helping each other. Join them; it only takes a minute: Sign up index out of bounds exception java up vote 0 down vote favorite 1 So the error message is this: Exception in
Array Index Out Of Bounds Exception Processing
thread "main" java.lang.IndexOutOfBoundsException: Index: 0, Size: 0 at java.util.ArrayList.rangeCheck(Unknown Source) at java.util.ArrayList.get(Unknown Source) at FcfsScheduler.sortArrival(FcfsScheduler.java:77) at FcfsScheduler.computeSchedule(FcfsScheduler.java:30) at ScheduleDisks.main(ScheduleDisks.java:33) with my code as public void sortArrival(List I getting array index out of bounds exception?say I have a method which among its arguments takes an int. I use that int in the method to index into an array which is an instance variable.in the first call array index out of bounds c++ of that method, intarg is zero. Why am I getting an exception when the array is guaranteed to array out of bound exception handling in c++ have a 0th element? private void someMethod(somearg, somearg, intarg) {....................................................................................myArray[intarg] += someint;}UpdateCancelAnswer Wiki10 Answers Chandra Mohan, Full Time Java professional now!Written 171w agoAs Apurva Nandan mentioned in the comment, http://stackoverflow.com/questions/15462649/index-out-of-bounds-exception-java looks to be a problem in the initialization code or hang on.. it can't be initialization error since then we would have had NullPointer.Do make sure the intarg is received as 0 and not any other number. Also make sure the intarg is not modified before reaching that part of the code in the method. (Parameters are not readonly and https://www.quora.com/Why-am-I-getting-array-index-out-of-bounds-exception can be modified.)12.6k Views · View UpvotesRelated QuestionsMore Answers BelowHow do I get rid of the runtime exception saying ArrayIndexOutOfBound at the line on which I declared a jagged array?What does "exception in thread main java.lang.Arrayindex out of bounds" means in java?What does this mean when I get an exception and I get null?Why am I getting "cannot find symbol"?Why am I getting Stub exception in Appium? Kaustubh SahaWritten 115w agoCheck the following :1. Is the int parameter arg being reinitialized somewhere in the method ? if not, may be consider making it final so as to avoid a red herring2. An array is not guaranteed to have a 0th element. Its perfectly legal to declare an array of size 0. In that case even arr[0] will give IndexOutofBoundsExceptionFor example, the following code will throw java.lang.ArrayIndexOutOfBoundsException :int[] arr = new int[0]; System.out.println(arr[0]);3. Consider enabling assertions and adding an assertion checking if the length of myArray is >= arg14.5k Views · View Upvotes Amar Chaitanya, Java developerWritten 50w agoArray index out of bounds exception occurs, for example, when here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with http://stackoverflow.com/questions/18549869/array-index-out-of-bounds-exception-java us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Array Index Out of Bounds Exception (Java) up vote 1 down vote favorite Here is my code: public class countChar { public static void main(String[] args) { int i; String userInput = new String(); userInput = Input.getString("Please enter a sentence"); int[] total out of = totalChars(userInput.toLowerCase()); for (i = 0; i < total.length; i++); { if (total[i] != 0) { System.out.println("Letter" + (char) ('a' + i) + " count =" + total[i]); } } } public static int[] totalChars(String userInput) { int[] total = new int[26]; int i; for (i = 0; i < userInput.length(); i++) { if (Character.isLetter(userInput.charAt(i))) { total[userInput.charAt(i) - 'a']++; } } return total; } } The program's purpose is to ask the user for a string, and then count the number of times each character out of bound is used in the string. When I go to compile the program, it works fine. When I run the program, I am able to enter a string in the popup box, but after I submit the string and press OK, I get an error, saying Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 26 at countChar.main(countChar.java:14) I'm not completely sure what the problem is or how to fix it. java arrays runtime-error share|improve this question edited Aug 31 '13 at 15:52 Makoto 55.1k1065116 asked Aug 31 '13 at 15:47 Boxasauras 6123 6 I think the for loop should enclose the if statement and the ; at the end is wrong. –Philip Whitehouse Aug 31 '13 at 15:51 Could you please indicate which line is line 14? (Use // <-- ArrayIndexOutOfBoundsException here) –Stewart Aug 31 '13 at 15:52 add a comment| 3 Answers 3 active oldest votes up vote 11 down vote for ( i = 0; i < total.length; i++ ); ^-- remove the semi-colon here With this semi-colon, the loop loops until i == total.length, doing nothing, and then what you thought was the body of the loop is executed. share|improve this answer edited Aug 31 '13 at 15:54 Philip Whitehouse 2,72421026 answered Aug 31 '13 at 15:52 JB Nizet 402k31529704 1 I feel a different formatting of the { (ie on the end of the for line) could have made this obvious. –Stewart Aug 31 '13 at 15:54 I updated the code, and I now Array Index Out Of Bound Exception In Android