Out Of Bounds Error Matlab
Contents |
Support Answers MathWorks Search MathWorks.com MathWorks Answers Support MATLAB Answers™ MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link matlab index out of bounds because size Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity
Index Out Of Bounds Java
Flagged Content Flagged as Spam Help MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader matlab index out of bounds because numel Link Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity Flagged Content Flagged as Spam Help Trial software ravi (view profile) 1 question 0 answers 0 matlab check if index out of bounds accepted answers Reputation: 0 Vote0 how to avoid index out of bounds error Asked by ravi ravi (view profile) 1 question 0 answers 0 accepted answers Reputation: 0 on 11 Apr 2014 Latest activity Answered by Ken Atwell Ken Atwell (view profile) 2 questions 334 answers 113 accepted answers Reputation: 777 on 12 Apr 2014 643 views
Row Index Out Of Bounds
(last 30 days) 643 views (last 30 days) hi,I am trying excute fallowing programme,but it is showing Attempted to access proj(2); index out of bounds because numel(proj)=1 error.I was not able to solve this problem.anybody know answer suggest me.thanks in advance. I = imread('ch_text.tiff'); [row ,col]=size(I); h_proj=zeros; for i = 1:row sum=0; for j=1:col if I(i,j)==0 %black pixel found sum=sum+1; end end h_proj(i)=sum; end figure,plot(h_proj,1:row),title('horizontal projection'); nonzero_row_indx=zeros; i = 1; k = 1; while (i >= 1) && (i <= row) if h_proj(i) ~= 0 nonzero_row_indx(k) = i; k = k + 1; i = i + 1; while h_proj(i) ~= 0 i = i + 1; end nonzero_row_indx(k) = i - 1; k = k + 1; end i = i + 1; end 1 Comment Show all comments Walter Roberson Walter Roberson (view profile) 27 questions 27,803 answers 9,720 accepted answers Reputation: 50,303 on 12 Apr 2014 Direct link to this comment: https://www.mathworks.com/matlabcentral/answers/125375#comment_207662 Your code does not have a variable named "proj" Tags index out of bou
Support Answers MathWorks Search MathWorks.com MathWorks Answers Support MATLAB Answers™ MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link index out of bounds python Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity index out of bounds r Flagged Content Flagged as Spam Help MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link
Index Out Of Bounds C++
Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity Flagged Content Flagged as Spam Help Trial software hamid shakeri (view profile) 3 questions 0 answers 0 https://www.mathworks.com/matlabcentral/answers/125375-how-to-avoid-index-out-of-bounds-error accepted answers Reputation: 0 Vote0 index out of bounds Asked by hamid shakeri hamid shakeri (view profile) 3 questions 0 answers 0 accepted answers Reputation: 0 on 21 Aug 2014 Latest activity Commented on by Geoff Hayes Geoff Hayes (view profile) 0 questions 2,010 answers 1,079 accepted answers Reputation: 5,652 on 22 Aug 2014 50 views (last https://www.mathworks.com/matlabcentral/answers/151809-index-out-of-bounds 30 days) 50 views (last 30 days) Hi I'm trying to execute a program but I keep getting this error:"Attempted to access indx(1); index out of bounds because numel(indx)=0" I understand what it means, but I'm not able to fixe it, I need some help.Here is the code with the error:[nel,dum]=size(Edof); ned=dum-1; [n,nsd]=size(Coord); [n,nd]=size(Dof); nend=ned/nen; % for i = 1:nel nodnum=zeros(1,nen); for j = 1:nen check=Dof(:,1:nend)-ones(n,1)*Edof(i,(j-1)*nend+2:j*nend+1); [indx,dum]=find(check==0); nodnum(j)=indx(1); end % Ex(i,:)=Coord(nodnum,1)'; if nsd>1 Ey(i,:)=Coord(nodnum,2)'; end if nsd>2 Ez(i,:)=Coord(nodnum,3)'; end end Thank you guys 0 Comments Show all comments Tags No tags are associated with this question. Products Global Optimization Toolbox Related Content 2 Answers Andrew Reibold (view profile) 15 questions 98 answers 25 accepted answers Reputation: 135 Vote0 Link Direct link to this answer: https://www.mathworks.com/matlabcentral/answers/151809#answer_149403 Answer by Andrew Reibold Andrew Reibold (view profile) 15 questions 98 answers 25 accepted answers Reputation: 135 on 21 Aug 2014 Edited by Andrew Reibold Andrew Reibold (view profile) 15 questions 98 answers 25 accepted answers Reputation: 135 on 21 Aug 2014 My assessme
Support Answers MathWorks Search MathWorks.com MathWorks Answers Support MATLAB Answers™ MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity Flagged https://www.mathworks.com/matlabcentral/answers/74613-attempted-to-access-x-2-index-out-of-bounds-because-numel-x-1-but-i-m-using-a-matrix Content Flagged as Spam Help MATLAB Central Community Home MATLAB Answers File Exchange Cody https://www.mathworks.com/matlabcentral/answers/54999-simulation-stopped-due-to-out-of-bounds-error Blogs Newsreader Link Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity Flagged Content Flagged as Spam Help Trial software mhowell (view profile) 1 question 0 answers 0 accepted answers Reputation: 0 Vote0 Attempted to access x(2); index out of bounds because numel(x)=1. But I'm using a matrix? Asked by mhowell mhowell (view out of profile) 1 question 0 answers 0 accepted answers Reputation: 0 on 4 May 2013 Latest activity Commented on by Pradeep Kumar R Pradeep Kumar R (view profile) 0 questions 2 answers 0 accepted answers Reputation: 0 on 25 Feb 2016 Accepted Answer by Azzi Abdelmalek Azzi Abdelmalek (view profile) 6 questions 7,115 answers 3,148 accepted answers Reputation: 15,763 820 views (last 30 days) 820 views (last 30 days) I'm just out of bounds trying to execute a simple for loop, but I keep getting this error "Attempted to access x(2); index out of bounds because numel(x)=1.Error in Quiz (line 11) x = x(i)" I don't understand what the error means. Any help would be appreciated!x = [22.5 45 67.5 90] for i=1:4 x = x(i) a = a(x) c = c(x) alpha = alpha(x) mu(a,c) end 0 Comments Show all comments Tags forloopsimple Products No products are associated with this question. Related Content 2 Answers Azzi Abdelmalek (view profile) 6 questions 7,115 answers 3,148 accepted answers Reputation: 15,763 Vote2 Link Direct link to this answer: https://www.mathworks.com/matlabcentral/answers/74613#answer_84400 Answer by Azzi Abdelmalek Azzi Abdelmalek (view profile) 6 questions 7,115 answers 3,148 accepted answers Reputation: 15,763 on 4 May 2013 Edited by Azzi Abdelmalek Azzi Abdelmalek (view profile) 6 questions 7,115 answers 3,148 accepted answers Reputation: 15,763 on 4 May 2013 Accepted answer After one itterationfor i=1:4 x = x(i) the length of x becomes equal to 1, then x(2) does not exist 0 Comments Show all comments Iman Ansari (view profile) 1 question 107 answers 55 accepted answers Reputation: 260 Vote1 Link Direct link to this answer: https://www.mathworks.com/matlabcentral/answers/74613#answer_84401 Answer by Iman Ansari Iman Ansari (view profile) 1 question 107
Support Answers MathWorks Search MathWorks.com MathWorks Answers Support MATLAB Answers™ MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity Flagged Content Flagged as Spam Help MATLAB Central Community Home MATLAB Answers File Exchange Cody Blogs Newsreader Link Exchange ThingSpeak Anniversary Home Ask Answer Browse More Contributors Recent Activity Flagged Content Flagged as Spam Help Trial software Emmanuel Luevano (view profile) 11 questions 0 answers 0 accepted answers Reputation: 0 Vote0 Simulation stopped due to out of bounds error Asked by Emmanuel Luevano Emmanuel Luevano (view profile) 11 questions 0 answers 0 accepted answers Reputation: 0 on 28 Nov 2012 41 views (last 30 days) 41 views (last 30 days) Hi, I'm running the next code into embedded matlab block from simulink, but when I run it, I have the next error message Simulation stopped due to out of bounds error, Enable debugging to pinpoint the location of the error.I did enable debugging and it keeps pinpoint the line of D(s,:) = inf , until I stopped appears the same error message Simulation stopped due to out of bounds error. Block Embedded MATLAB Function (#19) While executing: none.Can anyone please help me with this..x=(54,2);function D = distmat(X) %DISTMAT Compute euclidian distance matrix from coordinates [n,dim] = size(X); D = zeros(n); for j = 1:n for k = 1:dim v = X(:,k) - X(j,k); D(:,j) = D(:,j) + v.*v; end end D = sqrt(D); %--------------------------------------------------------------function p = greedy(s,D) n = size(D,1); p = zeros(1,n,'uint16'); p(1) = s; for k = 2:n D(s,:) = inf; [junk,s] = min(D(:,s)); p(k) = s; end 3 Comments Show all comments Kaustubha Govind Kaustubha Govind (view profile) 0 questions 2,204 answers 825 accepted answers Reputation: 4,816 on 28 Nov 2012 Direct link to this comment: https://www.mathworks.com/matlabcentral/answers/54999#comment_114075 Who is calling the function greedy? It looks like the argument 's' is large than 'n' (I'm assuming the second argument D is the same that constructed by the function distmat) Emmanuel Luevano Emmanuel Luevano (view profile) 11 questions 0 answers 0 accepted answers Reputation: 0 on 29 Nov 2012 Direct link to this comment