Out Of Bounds Exception Error
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Array Index Out Of Bounds C++
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Arrayindexoutofboundsexception In Java Example
Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up index out of bounds exception java up vote 0 down https://examples.javacodegeeks.com/java-basics/exceptions/java-lang-arrayindexoutofboundsexception-how-to-handle-array-index-out-of-bounds-exception/ vote favorite 1 So the error message is this: Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 0, Size: 0 at java.util.ArrayList.rangeCheck(Unknown Source) at java.util.ArrayList.get(Unknown Source) at FcfsScheduler.sortArrival(FcfsScheduler.java:77) at FcfsScheduler.computeSchedule(FcfsScheduler.java:30) at ScheduleDisks.main(ScheduleDisks.java:33) with my code as public void sortArrival(List I getting array index out of bounds exception?say I have a method which among its arguments takes an int. I https://www.quora.com/Why-am-I-getting-array-index-out-of-bounds-exception use that int in the method to index into an https://coderanch.com/t/596073/java/Array-Index-Bounds-Exception array which is an instance variable.in the first call of that method, intarg is zero. Why am I getting an exception when the array is guaranteed to have a 0th element? private void someMethod(somearg, somearg, intarg) {....................................................................................myArray[intarg] += someint;}UpdateCancelAnswer Wiki10 Answers Chandra Mohan, out of Full Time Java professional now!Written 171w agoAs Apurva Nandan mentioned in the comment, looks to be a problem in the initialization code or hang on.. it can't be initialization error since then we would have had NullPointer.Do make sure the intarg is received as 0 and not any other number. Also make sure out of bound the intarg is not modified before reaching that part of the code in the method. (Parameters are not readonly and can be modified.)12.6k Views · View UpvotesRelated QuestionsMore Answers BelowHow do I get rid of the runtime exception saying ArrayIndexOutOfBound at the line on which I declared a jagged array?What does "exception in thread main java.lang.Arrayindex out of bounds" means in java?What does this mean when I get an exception and I get null?Why am I getting "cannot find symbol"?Why am I getting Stub exception in Appium? Kaustubh SahaWritten 115w agoCheck the following :1. Is the int parameter arg being reinitialized somewhere in the method ? if not, may be consider making it final so as to avoid a red herring2. An array is not guaranteed to have a 0th element. Its perfectly legal to declare an array of size 0. In that case even arr[0] will give IndexOutofBoundsExceptionFor example, the following code will throw java.lang.ArrayIndexOutOfBoundsException :in This Site Careers Other all forums Forum: Beginning Java Array Index Out Of Bounds Exception barry richard Greenhorn Posts: 19 posted 3 years ago Hi all, I am trying to run this public class Example{ public static void main(String args []){ int ram[] = {1,2,3,4,5}; changeArray(ram); for(int y:ram)System.out.println(y); } public static void changeArray(int x[]){ for(int count=0;count<=x.length;count++){ x[count]+=5; } } } I get Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 5 at Example.changeArray(Example.java:13) at Example.main(Example.java:7) I am fairly certain that there is no errors in there, What could the problem be? Thanks barry richard Greenhorn Posts: 19 posted 3 years ago Just some more explanation, I am sure you pros can see it just by looking but What I am trying to do is to read the Array and add a number to each value and then print it thanks Jeff Verdegan Bartender Posts: 6109 6 I like... posted 3 years ago barry richard wrote: I am fairly certain that there is no errors in there I should hope that after seeing the error message, you would be completely certain that there are errors. Just like in your other thread, the error message is telling you exactly what's wrong. It's telling you that at line 13 of Example.java, you are trying to access the 6th element (at index 5) of an array that has less than 6 elements (and therefore indices 0..4 at the most). barry richard Greenhorn Posts: 19 posted 3 years ago Ok Resolved I needed to remove = for <=. Can anybody tell me why = needs to be removed? barry richard Greenhorn Posts: 19 posted 3 years ago Thanks Jeff, But why <= did not work? Thanks Jeff Verdegan Bartender Posts: 6109 6 I like... posted 3 years ago barry richard wrote:Thanks Jeff, But why <= did not work? Thanks Well, what's the difference between < and <