Out Of Scope Error
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Jshint Used Out Of Scope
Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 out of scope meaning million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up JSLint “out of scope” error due to function ordering? up vote 1 down vote favorite JSLint seems to be picky
Out Of Scope Java
about function ordering. This passes fine: function a() { 'use strict'; return 1; } function b() { 'use strict'; a(); } While this gives an 'a' is out of scope error message: function b() { 'use strict'; a(); } function a() { 'use strict'; return 1; } Is this by design? Should I care? How can it be avoided in larger (more complex) cases, where it might not always be possible to give out of scope driving the functions a clear order? javascript jslint share|improve this question asked Jan 5 at 14:49 Codemonkey 93221022 The error should be something like, Functions should be defined before using them –Tushar Jan 5 at 14:50 2 "JSLint seems to be picky about function ordering." — Yes, it is. For that matter… "JSLint seems to be picky" is true as well. –Quentin Jan 5 at 14:51 Some linters want you to define functions before they are referenced, JavaScript doesn't care though. –Juan Mendes Jan 5 at 14:53 2 stackoverflow.com/questions/7609276/… –epascarello Jan 5 at 14:54 The comment from @epascarello is absolutely essential here. This ordering warning really is an error worth addressing (see answer, below). Also, do you have an example of "where it might not always be possible to give the functions a clear order"? Usually, as I remark below, that's a code smell worth checking out. –ruffin Jan 5 at 15:34 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote accepted JSLint/JSHint expect you to define functions before you reference them. However, JavaScript doesn't care because functions and variables are hoisted. You can change your code style, or tell the linter to ignore it using http://jshint.com/docs/options/#latedef /* jshint latedef:nofunc */ function b() {
your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To http://www.webdeveloper.com/forum/showthread.php?74176-what-does-quot-out-of-scope-quot-mean-! start viewing messages, select the forum that you want to visit from the selection below. Results 1 to 5 of 5 Thread: what does "out of scope" mean?! Tweet Thread Tools Show Printable Version Email https://www.codecademy.com/en/forum_questions/4f45f12dd160e400030141e8 this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 07-28-2005,09:27 AM #1 hitecbill View Profile View Forum Posts Visit Homepage Registered User Join Date Mar 2005 out of Location planet earth Posts 121 what does "out of scope" mean?! (in regards to error handling) "this statement goes out of scope when control exits out of the procedure in which it is written" i know what's going on, but what does it mean in english?! http://img99.imageshack.us/img99/5331/outofscope1cl.gif Reply With Quote 07-28-2005,08:08 PM #2 buntine View Profile View Forum Posts Visit Homepage Super Moderator Join Date Jan 2004 Location Melbourne, Australia out of scope Posts 5,298 It may be referring to the statement trying to access data/variables that it does not have access to, and are therefore "out of scope". In strict languages, if you define a variable within a function, it can then not be referenced from the calling environment. Regards. http://www.andrewbuntine.com Reply With Quote 07-29-2005,09:55 AM #3 hitecbill View Profile View Forum Posts Visit Homepage Registered User Join Date Mar 2005 Location planet earth Posts 121 thx for the reply, hmm, well "On Error Then GoTo 0" is what it's referring to... here's the full text: "The On Error Then GoTo 0 statement is used to disable error handling for the procedure in which it is written. This statement goes out of scope when control exits out of the procedure in which it is written. Therefore errors occurring from this point onwards will not be handled by the error handling routine" weird english...i don't see that the "scope" is that it is going out of... Last edited by hitecbill; 07-29-2005 at 09:57 AM. Reply With Quote 08-03-2005,03:56 PM #4 Adamal View Profile View Forum Posts Registered User Join Date Aug 2005 Posts 5 Those who program using VBScript may not necessarily be aware of what "scope" means. Wh
points Submitted by Brady Banks over 4 years ago toatlTime used out of Scope I keep getting an error on the var averageTime line that says "totalTime used out of scope". If I put averageTime inside the For loop the error goes away but I get the wrong answer. Can anyone explain? var calculateAverage = function (raceTimes) { for ( i = 0; i < raceTimes.length; i++ ) { var totalTime = (totalTime || 0) + raceTimes[i]; } // assign variable averageTime var averageTime = (totalTime / raceTimes.length); return averageTime; }; 0 votes permalink I had a similar error but the rest of the code was fine and allowed it to continue. I modified my code in later examples like so: `var calculateAverage = function (raceTimes) { for ( i = 0; i < raceTimes.length; i++ ) var totalTime = (totalTime || 0) + raceTimes[i]; }; var averageTime = totalTime / raceTimes.length;` I'm not experienced enough to be positive, but I think the out of scope error is because when it is inside the function (as denoted by the curly brace) it isn't fully assigned. Once the function completes the value is available for use. I could be way off as to the cause, but the fix I posted is valid =) 933 points Submitted by repairmanski over 4 years ago 0 votes permalink If you declare totalTime outside of the for loop, you don't have this issue. I'm a novice myself, but much like declaring local variables within a function, declaring totalTime within the for loop is perhaps a similar concept? 656 points Submitted by mottavibrannon over 4 years ago